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Galina-37 [17]
3 years ago
10

Joel is laying pipe for a sprinkler system before he plants his lawn. The lawn is a rectangle, 15 feet long and 8 feet wide. He

needs to lay a piece of pipe that will be run along the diagonal of the lawn. It will divide the area of the lawn into two right triangles. What will be the length of that diagonal piece of pipe?
Mathematics
2 answers:
alisha [4.7K]3 years ago
3 0
17 ft because you have to use Pythagorean Theorem,  which is a squared + b squared = c squared. After that you take the square root of "c squared".


aliina [53]3 years ago
3 0

I need help on this too

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y=1

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Please help<br><br>Select all of the non-real complex numbers in the given table.​
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All the expressions that have a negative in the radical

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leg = root 5
Other leg is also root 5
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3 years ago
Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra
bearhunter [10]

Answer:

\frac{dh}{dt}=-\frac{1}{2\pi}cm/min

Step-by-step explanation:

From similar triangles, see diagram in attachment

\frac{r}{4}=\frac{h}{16}


We solve for r to obtain,


r=\frac{h}{4}


The formula for calculating the volume of a cone is

V=\frac{1}{3}\pi r^2h


We substitute the value of r=\frac{h}{4} to obtain,


V=\frac{1}{3}\pi (\frac{h}{4})^2h


This implies that,

V=\frac{1}{48}\pi h^3


We now differentiate both sides with respect to t to get,

\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}


We were given that water is drained out of the tank at a rate of 2cm^3/min


This implies that \frac{dV}{dt}=-2cm^3/min.


Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means h=8cm.


We substitute this values to obtain,


-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}


\Rightarrow -2=4\pi \frac{dh}{dt}


\Rightarrow -1=2\pi \frac{dh}{dt}


\frac{dh}{dt}=-\frac{1}{2\pi}






3 0
3 years ago
Read 2 more answers
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