Answer:
b
Step-by-step explanation:
fairly certain it is b
9514 1404 393
Answer:
1. (f+g)(x) = 2x^2 +4x +2
2. (f -g)(x) = -2x^2 +4x -4
5. (f+g)(x) = x^2 +2x -1
6. (g -f)(x) = x^2 -2x -1
Step-by-step explanation:
None of these are compositions. They are only sums or differences.
(f±g)(x) = f(x) ± g(x)
__
1. (f+g)(x) = f(x) +g(x) = (4x -1) +(2x^2 +3)
(f+g)(x) = 2x^2 +4x +2
__
2. (f -g)(x) = f(x) -g(x) = (4x -1) -(2x^2 +3)
(f -g)(x) = -2x^2 +4x -4
__
5. (f +g)(x) = f(x) +g(x) = (2x) +(x^2 -1)
(f+g)(x) = x^2 +2x -1
__
6. (g -f)(x) = g(x) -f(x) = (x^2 -1) -(2x)
(g -f)(x) = x^2 -2x -1
If a point
(
x
,
y
)
is written as
(
r
,
θ
)
in polar coordinates, then
x
=
r
o
s
θ
and
y
=
r
sin
θ
.
As such in polar form equation
x
=
−
3
can be written as
r
cos
θ
=
−
3
or
r
=
−
3
cos
θ
Answer:
Angle CAD is 44 degrees
Angle ACD is 44 degrees
Angle ACB is 136 degrees
Angle ABC is 22 degrees
Explanation:
29. Triangle ADC is an isosceles triangle because it has two equal sides.
If segments AD and DC are congruent, then segment AC is the base and the base angles of an isosceles triangle are equal.
Let x be angle CAD.
Let's go ahead x;
Therefore, measure of angle CAD is 44 degrees.
30. Measure of angle ACD is 44 degrees (Base angles of an isosceles triangle are equal)
31. Let angle ACB be y,
Let's go ahead and find measure of angle ACB;
So measure of angle ACB is 136 degrees.
32. Let angle ABC be z.
Triangle ACB is also an isosceles triangle so the base angles are the same.
Let's go ahead and find z;
So measure of angle ABC is 22 degrees.
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
