The horizontal distance until the plan flies over the island is 2687.05 feet approximately.
<u>Solution:</u>
Given that, A plane at an altitude of 7000 ft is flying in the direction of an island
An angle of depression is 21 degree from the plane to the island
We have to find what is the horizontal distance until the plan flies over the island
The diagram is attached below
Assume as shown in the diagram
, now we can use the right angle triangle property
Hence, the distance between plane and point above island is 2687.05 feet approximately.
Answer:
Ix = Iy = 
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is 
. Moment of inertia of quarter disk about its perpendicular is 
.
Now using perpendicular axis theorem, Ix = Iy = 
= .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Right isosceles, which has two sides the same length and one angle that measures 90 degrees.
Answer:
D) 12x² - 20x + 7
Step-by-step explanation:
Use FOIL when multiplying 2 binomials...
FOIL is Firsts, Outsides, Insides, Lasts. It's the order in which you multiply the numbers in the binomials...
(2x - 1)(6x - 7)
Firsts: (2x)(6x) = 12x²
Outsides: (2x)(-7) = -14x
Insides: (-1)(6x) = -6x
Lasts: (-1)(-7) = 7
Now add them up...
12x² - 14x - 6x + 7
12x² - 20x + 7
