Factor 3y 2 - 4y. a. y(4 - 3y) b.y(3y - 4) c.y(4y - 3)
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Answer:
The probability of rolling a doubles or getting two numbers whose sum is equal to 8 is 0.278.
Step-by-step explanation:
There are a total of <em>N</em> = 36 outcomes when rolling two fair dice.
The outcomes for rolling doubles are: {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}.
So, n (Doubles) = n (D) = 6
The outcomes for rolling a sum of 8 are: {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}
So, n (Sum 8) = n (S8) = 5
Considering the outcomes of the above two events, it can be seen that there is a common outcome, i.e. (4, 4).
So, n (D ∩ S8) = 1
Compute the probability of rolling a doubles or getting two numbers whose sum is equal to 8 as follows:
Thus, the probability of rolling a doubles or getting two numbers whose sum is equal to 8 is 0.278.