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Sindrei [870]
2 years ago
10

Sum of numbers 975,983,923,913 and 985 rounded upto hundredth place is​

Mathematics
1 answer:
nikitadnepr [17]2 years ago
3 0
4,779 if you are just adding to find the sun of the numbers
You might be interested in
Find the missing side of a triangle with leg length 10 yards and Hypotenuse 26 yards?
Elan Coil [88]

Answer:

The answer is 24 yards.

Step-by-step explanation:

a² + b² = c²

10² + b² = 26²

100 + b = 676

676 - 100 = 576

√576 = 24 yards

7 0
3 years ago
The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

Z = 2.14 has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

8 0
3 years ago
Add the following numbers a)and b)<br>answers please ​
Drupady [299]
Answer: a) 3 2/3, b) 5 2/5

Explanation:

a) 5/3 + 6/3 = 11/3 = 3 2/3

b) 12/5 + 15/5 = 27/5 = 5 2/5
4 0
3 years ago
Read 2 more answers
1 2/12 - 2/12 - 1/12=
aleksley [76]

Answer:

11/12

Step-by-step explanation:

1 2/12 = 14/12

14/12 - 2/12 - 1/12

since they all have 12, it doesn't matter until the end

14 - 2 = 12 - 1 = 11

put the /12 behind the 11 and you have an answer

7 0
3 years ago
Find the equation of the line through the point (2, 5) that cuts off the least area from the first quadrant. Give your answer us
Amanda [17]

The equation of the line would be

y = mx+b 

where m is the slope, b is the y intercept. 

<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept and the base is y intercept divided by slope. Therefore,</span>

A = b^2/2m

At point (2,5)

5 = 2m+b

Substitute that in the area

A = b^2/5-b to find the least area, differentiate the area with respect to the height and equate it to 0 

dA/db = 0

<span>find b and use that to find m. Then, you can have the equation of the line.</span>


4 0
3 years ago
Read 2 more answers
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