Can anyone help with this please
2 answers:
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Answer:
E is not a subspace of
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
Answer:
d) 5/12
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Drinks:
Five diet, 10 regular.
Probability of a regular drink:
10/(10+5) = 10/15 = 2/3
Regular bag of chips:
6 fat-free, 10 regular
Probability of a regular bag of chips:
10/(10+6) = 10/16 = 5/8
What is the probability that you will buy a regular drink and a regular bag of chips?
Drink and chips are independent events, which means that we just multiply the probabilities. So
The correct answer is given by option d.