Well, what you're going to do is.. turn 3 1/2 into an irregular fraction.
3 = 6/2
we still have the initially 1/2 left so we will add that.
7/2
now we want to change it so that the denominator is equal to 4 so we multiply both top and bottom by 2
14/4
now we divide the 14 by 3 and you will get approximately 4. we will ignore the rest because it asks for whole servings and 3 only goes nicely into 14 4 times
Answer:
The domain of the function is all real values of x, except
and 
Step-by-step explanation:
We are given the following function:

It's a fraction, so the domain is all the real values except those in which the denominator is 0.
Denominator:
Quadratic equation with 
Using bhaskara, the denominator is 0 for these following values of x:



The domain of the function is all real values of x, except
and 
Answer:
210
Step-by-step explanation:
The volume of a cone is the base * height / 3. We know the base is 45 and the height is 14, so that means the volume is 45 * 14 / 3 = 210
It has a density of <span>997 kg/m³ </span>