Y=mx+b
7=6(3)+b
7-18=b
b=-11
y=6x-11 (i guess that is the answer)
A rectangle or a parallelogram is a polygon with only 2 congruent sides and 2 congruent angles.
Answer:
1. x = -1.5y
2. 5 (2x-3)
3. p = 4
Step-by-step explanation:
1) Simplifying
7x + 2y + -3x + 4y = 0
Reorder the terms:
7x + -3x + 2y + 4y = 0
Combine like terms: 7x + -3x = 4x
4x + 2y + 4y = 0
Combine like terms: 2y + 4y = 6y
4x + 6y = 0
Solving
4x + 6y = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-6y' to each side of the equation.
4x + 6y + -6y = 0 + -6y
Combine like terms: 6y + -6y = 0
4x + 0 = 0 + -6y
4x = 0 + -6y
Remove the zero:
4x = -6y
Divide each side by '4'.
x = -1.5y
Simplifying
x = -1.5y
2)
Common factor
10x - 15
5 (2x-3)
3) Simplifying
5p = 3p + 8
Reorder the terms:
5p = 8 + 3p
Solving
5p = 8 + 3p
Solving for variable 'p'.
Move all terms containing p to the left, all other terms to the right.
Add '-3p' to each side of the equation.
5p + -3p = 8 + 3p + -3p
Combine like terms: 5p + -3p = 2p
2p = 8 + 3p + -3p
Combine like terms: 3p + -3p = 0
2p = 8 + 0
2p = 8
Divide each side by '2'.
p = 4
Simplifying
p = 4
Let’s say it takes time t hours for the interception.
In that time the carrier travels 28t nm west and the helicopter 130t nm.
Now we use the sine rule to find the angle x which lies between the distance 175 and 130t.
sin(x)/28t=sin35/130t. So sin(x)=28sin35/130=14sin35/65=0.1235 and x=7.0964 degrees.
Therefore the helicopter should use a bearing of 35+7.0964=42.0964 degrees north of east or 47.9 degrees east of north approx.
3(2x+5)(2x-5), 5 is the missing term.