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xenn [34]
3 years ago
7

THere an infinite number of line segments on a line. TRUE OR FALSE

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0
It is true hope this helped
Georgia [21]3 years ago
5 0
The answer to this is True.
You might be interested in
1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+10 times 2
Maksim231197 [3]

Answer:

200

Step-by-step explanation:

<u>Step 1:  Add</u>

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

21 + 7 = 28

28 + 8 = 36

36 + 9 = 45

45 + 1 = 46

46 + 2 = 48

48 + 3 = 51

51 + 4 = 55

55 + 5 = 60

60 + 6 = 66

66 + 7 = 73

73 + 8 = 81

81 + 9 = 90

90 + 10 = 100

<em>100</em>

<u>Step 2:  Multiply</u>

100 * 2

<em>200</em>

Answer:  200

6 0
2 years ago
Factorise 15x-5 <br> factorise x^2-5x+6
kotegsom [21]
5(3x-1) (x-3)(x-2) I don't know if you want working out or an explanation? Or if it's too late, sorry.
5 0
2 years ago
(08.06 MC)
Aleks04 [339]
A. 2x+y=25; x+y=20
x represents cheese wafers and y represents chocolate wafers.

B. I will choose elimination since there is y and y. I can multiply one equation by -1 to get y and -y, which cancels out.
2x+y=25
-x-y=-20

Add equations
x=5

Plug x in
5+y=20
y=15

Final answer: 5 cheese wafers, 15 chocolate wafers
3 0
3 years ago
STOP SENDING ME LINKS BUT I NEED HELP RN
Strike441 [17]
45
1080 divided by 24
45

45 5lbs per hour
6 0
2 years ago
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.
lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

H_0: \mu \leq 220000

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

H_1: \mu > 220000.

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem:

\overline{x} = 226450, \mu = 220000, s = 11500, n = 23

Then, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}

t = 2.69

We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0
2 years ago
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