name at least two Coastal features that are shaped by erosion and two costal features that are shaped by deposition

Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6 y = x3 – x2 + 10x + 6 y = 0 y = x3 –

Maslowich

Answer:

answer is:

$y=x^{3}-10 x,y=x^{2}-6$

Step-by-step explanation:

we are asked to find which system of equations can we use to find the roots of the equation:

$x^{3}-10x=x^{2}-6$

since the system of equation in last part is given as:

$y=x^{3}-10 x,y=x^{2}-6$

so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:

$x^{3}-10x=x^{2}-6$ .

3 0

3 years ago

Read 2 more answers

The measure of a side of a square is x units. A new square is formed with each side 6 units longer than the original squares sid

xenn [34]

We know that
[area old square]=x*x--------> x²

[area new square]=(x+6)*(x+6)-------> (x+6)²-----> A=x²+12x+36

the answer is
An <span>expression to represent the area of the new square is (</span>x²+12x+36)

4 0

3 years ago

CAN U GUYS PELASE ANSWER THE SIMULTANEOUS EQUATION QUESTION QUESTIONS ASAP. THIS IS EXTREMELY URGENT. Solve it by using the subs

prisoha [69]

Answer:

a ) y = 1 and x = -1

d) y = 5 and x = -1/2

Step-by-step explanation:

<h2><u>Substitution method</u></h2><h2><u>Question a</u></h2>

y = x+ 2

y = 2x + 3

<em>we can make the first formula in terms of x , so we can place in into the second formula</em>

y = x + 2

x = y - 2

now put y - 2 where x is in the second equation

y = 2x + 3

y = 2(y - 2) + 3

y = 2y - 4 +3

now solve

4 - 3 = 2y -y

y = 1

since y = 1 we can find what x is by putting into the first formula

y = x +2

x = y - 2

x = (1) -2

x = -1

<h3><u>hence y = 1 and x = -1 </u></h3><h3><u /></h3><h2><u>Question d</u></h2>

y = 2x + 6

y = 4 - 2x

<em>we can make the first formula in terms of x , so we can place in into the second formula</em>

y = 2x + 6

y - 6 = 2x

x = (y-6)/ 2

now place (y-6)/2 where x is in the second formula

y = 4 -2x

y = 4 - 2 ( $\frac{y - 6}{2}$ )

now solve

the multiplication by 2 and division by 2 are cancelled out

hence making the simplified equation as:

y = 4 - y + 6

2y = 4 + 6

2y = 10

y = 5

now place this into the first equation

y = 2x + 6

y - 6 = 2x

x = (y-6)/ 2

x = (5-6)/2

x = -1/2

<h3><u>hence y = 5 and x = -1/2</u></h3>

6 0

4 years ago

Please help asap! Will give brainliest! Please answer correctly! No guessing. Check all that apply.

bearhunter [10]

Answer:F

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

(4) A spherical balloon is being inflated so that its diameter is increasing at a constant rate of 6 cm/min. How quickly is the

fredd [130]

In terms of its radius $r$ , the volume of the balloon is

$V(r)=\dfrac{4\pi}3r^3$

The diameter $d$ is twice the radius, so that in terms of its diameters, the balloon's volume is given by

$V(d)=\dfrac{4\pi}3\left(\dfrac d2\right)^3=\dfrac\pi6d^3$

Differentiate both sides with respect to time $t$ :

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2d^2\dfrac{\mathrm dd}{\mathrm dt}$

The diameter increases at a rate of $\frac{\mathrm dd}{\mathrm dt}=6\frac{\rm cm}{\rm min}$ . When the diameter is $d=50\,\mathrm{cm}$ , we have

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2(50\,\mathrm{cm})^2\left(6\frac{\rm cm}{\rm min}\right)=7500\pi\dfrac{\mathrm{cm}^3}{\rm min}$

or about 23,562 cc/min (where cc = cubic centimeters)

5 0

3 years ago