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4 years ago

What is the solution to this equation x/5=15 a.x=75 b.x=20 c.x=3 d.x=10

Mathematics

1 answer:

Darina [25.2K]4 years ago

8 0

$\dfrac{x}{5}=15\ \ \ \ |\cdot5\\\\\not5\cdot\dfrac{x}{\not5}=5\cdot15\\\\x=75$

Answer: a. x = 75

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The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for

MrRissso [65]

Part A: Let the September price be x, then
1.2x = 1.5
x = 1.5/1.2 = 1.25
Therefore, September price is $1.25

Part B: In September, they earned 0.4 * 1.25 * 900 = $450
In October, they earned 0.4 * 1.5 * 700 = $420
Therefore, they earned more money in September.

8 0

3 years ago

Caroline's gross annual salary is $47,448 What is the max amount of rent she can afford to pay?

morpeh [17]

47,448/12=$3954

As, 28/36 rule states that maximum of 28% of your monthly expenditure should be spent on housing finances.

0.28*3954=$1107,12

Answer: $1107.

4 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago

A map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 miles. What

e-lub [12.9K]

Answer:

Actual area = 21600 Sq.miles

Step-by-step explanation:

We are given;

length; L = 4 inches

Width; W = 6 inches

The scale of the map; 1 inch for every 30 miles i.e. 1 : 30

Since the scale is 1:30, let's find the find the actual dimensions and then the actual area

For the Length,

Since 1 inch represents 30 miles,

Then, 4 inches = (4 × 30)/1 = 120 miles

For the width;

Since 1 inch represents 30 miles,

Then,6 inches = (6 × 30)/1 = 180 miles

Therefore, the actual dimensions are 120 miles and 180 miles

Now, formula for area of rectangle = length × width

Thus;

Actual area = 120 × 180

Actual area = 21600 Sq.miles

8 0

3 years ago

Part of arianna's earnings are based on a 5% commission rate. At the end of the day arianna earned 14.98 in commission. How much

Furkat [3]

Answer:

$299.60

Step-by-step explanation:

The relationship between earnings and sales is ...

earnings = 5% × sales

$14.98 = 0.05 × sales

$14.98/0.05 = sales = $299.60

Arianna sold $299.60 that day.

5 0

3 years ago