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2 years ago

It appears that the derivatives of sine and cosine are related. What about the second derivatives?.

Mathematics

1 answer:

Andru [333]2 years ago

5 0

Answer:

Step-by-step explanation:

$\frac{d}{dx} (sin~x)=cos~x\\\frac{d}{dx}(cos~x) =-sin~x\\\frac{d^2}{dx^2} (sin~x)=\frac{d}{dx} (cos~x)=- sin~x\\\frac{d^2}{dx^2} (cos~x)=\frac{d}{dx} (-sin~x)=-cos~x$

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The answer and how you got the answer

olasank [31]

Answer:

$\frac{34}{15}$

Step-by-step explanation:

we are asked to evaluate

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

Above we are given mixed fraction which can be converted in proper fraction using formula given below

$a\tfrac{b}{c}=\frac{a \times c +b}{c}$

Hence

$4\tfrac{1}{4}=\frac{4 \times 4 +1}{4}$

$4\tfrac{1}{4}=\frac{17}{4}$

Also

$1\tfrac{7}{8}=\frac{1 \times 8 +7}{8}$

$1\tfrac{7}{8}=\frac{15}{8}$

Hence

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

can be written as

$\frac{17}{4}$ ÷ $\frac{15}{8}$

Also we know the rule for dividing fraction is as given below

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{a}{b} \times \frac{d}{c}$

Hence

$\frac{17}{4}$ ÷ $\frac{15}{8}$ = $\frac{17}{4} \times \frac{8}{15}$

= $\frac{17 \times 2}{15}$

= $\frac{34}{15}$

8 0

2 years ago

Imagine a pond. In it sits one lilypad, which reproduces once a day. Each of its offspring also reproduces once a day, doubling

sergeinik [125]

Answer: On the 29th day

Step-by-step explanation:

According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.

On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.

The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are $2^{30}$ lilypads on the 30th, and $2^{29}$ lilypads on the 29th. This can be deduced multiplying succesively by 2.