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3 years ago

It appears that the derivatives of sine and cosine are related. What about the second derivatives?.

Mathematics

1 answer:

Andru [333]3 years ago

5 0

Answer:

Step-by-step explanation:

$\frac{d}{dx} (sin~x)=cos~x\\\frac{d}{dx}(cos~x) =-sin~x\\\frac{d^2}{dx^2} (sin~x)=\frac{d}{dx} (cos~x)=- sin~x\\\frac{d^2}{dx^2} (cos~x)=\frac{d}{dx} (-sin~x)=-cos~x$

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Determine the equation of the line. (slope intercept form)

Taya2010 [7]

Answer:

y=x-4

Step-by-step explanation:

y=mx+b

m : slope : 1

b : y-int : -4

5 0

3 years ago

A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(

alekssr [168]

Answer:

$\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right)$ or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

$\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1$

Set $f'(x)$ equal to 8/7 and solve for x:

$\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}$

Therefore, $f(x)$ will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into $f(x)$ to get the y-coordinate:

$\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}$

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

5 0

3 years ago

For c = d(3.14), what is c when d = 100 show work

Katyanochek1 [597]

Answer:314

Step-by-step explanation: 3.14 x 100 = 314

Move the decimal two times to the right because there is two zeros

5 0

3 years ago

1. Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the

Sveta_85 [38]

Answer:

#1) y = -4x + 1; #2) parallel; #3) y = -1/2x + 5/2; #4) y = 2x + 4; #5) Never

Step-by-step explanation:

#1) We want a line that passes through (1, -3) and is parallel to y = 2-4(x-1). First we simplify our equation using the distributive property:

y = 2-4(x-1) = 2-4(x) -4(-1) = 2-4x--4 = 2-4x + 4 = -4x + 6

Lines that are parallel have the same slope; this means we want a line through (1, -3) with a slope of -4. Using point-slope form,

$y-y_1=m(x-x_1)\\\\y--3=-4(x-1)\\\\y+3=-4(x)-4(-1)\\\\y+3=-4x+4\\\\y+3-3=-4x+4-3\\\\y=-4x+1$

#2) We must first write our second equation in slope-intercept form by isolating the y term:

2x+y=7

Subtract 2x from each side"

2x+y-2x = 7-2x

y = -2x+7

This means the slope is -2; the slopes are the same, so the lines are parallel.

#3) The slope of our given equation is 2. To be perpendicular, the second line must have a slope that is a negative reciprocal (flipped and opposite signs); this makes it -1/2. Using point-slope form,

$y-0=\frac{-1}{2}(x-5)\\\\y=\frac{-1}{2}(x)+\frac{-1}{2}(-5)\\\\y=\frac{-1}{2}x+\frac{5}{2}$

#4) The slope of Main Street on the diagram, found by using rise/run, is 2. This means the bike path will also have a slope of 2 in order to be parallel. The park entrance is at (0, 4). This makes the equation y = 2x+4.

#5) Two lines with the same slope are always parallel. They are never perpendicular.

3 0

3 years ago

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Measures of minor arcs equal measures of inscribed angles.<br> true or false?

Vikki [24]

The answer to your question is TRUE

8 0

3 years ago

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