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adelina 88 [10]
4 years ago
5

Maggie was doing research for her Ph.D. in physics when a 12 mg sample of radioactive material decayed to 3 mg in 26 minutes. De

termine the half life of this substance.
Mathematics
1 answer:
netineya [11]4 years ago
3 0

The general way to work this out is to solve the general expression for
the remaining quantity versus half-life, using logarithms.  But that's not
necessary with these numbers.

Look at the numbers:

-- 3 mg is  1/4  of  12 mg.

-- 1/4  is the product of  (1/2) x (1/2).

-- So the  3 mg is what's left of  12 mg after  2  half-lives.
The  26  minutes must be two half-lives.

-- The half-life of that substance is  26/2 = <em>13 minutes</em>.

Go Maggie !

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Answer: At a 5% significance level, the critical value is <u>1.690</u>.

Step-by-step explanation:

Let \mu denotes the average concentration of radon gas.

Given : A school teacher is worried that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.

As per given , the appropriate hypothesis to test :

\text{Null hypothesis }:H_0:\mu\leq4

\text{Alternative hypothesis }:H_a:\mu>4

[Note : Alternative hypothesis used to express strictly greater than or less than signs and null hypothesis is opposite of it.]

∵ alternative hypothesis is right tailed , so the test must be a right tailed test (one-tailed test.)

Also the population standard deviation is unknown , so we use t-test.

[Note : we have given sample standard deviation as s=1pCi/L. ]

Sample size : 36

Then , degree of freedom = n-1=35

Now, for \alpha=0.05 level of significance, the right-tailed critical value would be

t_{df, \alpha}=t_{35,0.005}=1.690      [Using the students' t-distribution table ]

Hence, At a 5% significance level, the critical value is t_{df, \alpha}=1.690.

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Let x = small number

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3 years ago
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