How is this problem done 5/2+2/3+n=1/6

Is there a answer to this

hodyreva [135]

Answer:

mean=71

Step-by-step explanation:

Mean x¯¯¯x¯

71

Median x˜x~

72

Mode

64, 83, 79, 38, 81, 90, 59, 93, 70, 73, 71, 51

Range

55

Minimum

38

Maximum

93

Count n

12

Sum

852

Quartiles

Quartiles:

Q1 --> 61.5

Q2 --> 72

Q3 --> 82

Interquartile

Range IQR

20.5

Outliers

none

5 0

3 years ago

In a survey of 90 students 20 choose rock.40 chose hip hop 30 chose country. In a school of 360 students how many would be expec

lina2011 [118]

Answer:

The students would be expected to choose rock be 80 or students choose hip hop be 160 or choose to country be 120.

Step-by-step explanation:

Given:

In a survey of 90 students 20 choose rock, 40 choose hip hop and 30 choose country.

Now, to find the students expected to choose hip hop or rock or country in a school of 360 students.

Let the number of students expected to choose rock be $x.$

Let the number of students expected to choose hip hop be $y.$

Let the number of students expected to choose country be $z.$

Total number of students = 360.

Now, to get the number of students choosing hip hop or rock or country by using cross multiplication method:

In a survey of 90 students 20 choose rock.

So, 90 is equivalent to 20.

Thus, 360 is equivalent to $x$ .

$\frac{90}{20} =\frac{360}{x} \\\\By\ cross\ multiplying\ we\ get:\\\\90x=7200\\\\Dividing\ both\ sides\ by\ 90\ we\ get:\\\\x=80.$

Thus, the number of students expected to choose rock is 80.

Now,

In a survey of 90 students 40 choose hip hop.

So, 90 is equivalent to 40.

Thus, 360 is equivalent to $y.$

$\frac{90}{40} =\frac{360}{y} \\\\By\ cross\ multiplying\ we\ get:\\\\90y=14400\\\\Dividing\ both\ sides\ by\ 90\ we\ get:\\\\y=160.$

Therefore, 160 students expected to choose hip hop.

And,

In a survey of 90 students 30 choose country.

So, 90 is equivalent to 30.

Thus, 360 is equivalent to $y.$

$\frac{90}{30} =\frac{360}{z} \\\\By\ cross\ multiplying\ we\ get:\\\\90x=10800\\\\Dividing\ both\ sides\ by\ 90\ we\ get:\\\\x=120.$

Hence, 120 students expected to choose country.

Therefore, the students would be expected to choose rock be 80 or students choose hip hop be 160 or choose to country be 120.

5 0

4 years ago

Pls help me this is my homework

nikklg [1K]

Answer

34 match sticks (C)

please mark me as brainliest and pls someone answer my question also

7 0

3 years ago

Read 2 more answers

Construct a 96% confidence interval if a sampling distribution has a mean of 20, a standard deviation of 5, and a size of 100.

MAXImum [283]

Using the t-distribution, the 96% confidence interval is given as follows:

(18.96, 21.04).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 96% confidence interval, with 100 - 1 = 99 df, is t = 2.0812.

The parameters are given as follows:

$\overline{x} = 20, s = 5, n = 100$

Hence the bounds of the interval are:

$\overline{x} - t\frac{s}{\sqrt{n}} = 20 - 2.0812\frac{5}{\sqrt{100}} = 18.96$

$\overline{x} + t\frac{s}{\sqrt{n}} = 20 + 2.0812\frac{5}{\sqrt{100}} = 21.04$

More can be learned about the t-distribution at brainly.com/question/16162795

#SPJ1

6 0

2 years ago

Write the value of each expression in standard form. Expression Standard Forr 2hundres×10 in standard form

nignag [31]

Write it as a power of 10
200 x 10
2 x 10^2

3 0

3 years ago