Answer: 7.5
Form your proportion. Let x be the width of QRST.
Length of ABCD Length of QRST
----------------------- = -------------------------
Width of ABCD Width of QRST
8/5 = 12/x
Solve for x by cross-multiplying.
(8)(x) = (12)(5)
8x = 60
x = 7.5
The perimeters of both are equal.
The side of the square is 12.
Therefore, its area equals to : 12² = 144
The rectangle base is 19.
Because it has the same perimeter as the square's, so rectangle perimeter is : 19 + 19 + side + side = 12 + 12 + 12 + 12
= 38 + 2side = 48
= 2side = 48 - 38
= side of rectangle = 5
Therefore, its area is 19 x 5 = 95
If you subtract it from the area of the square, you will get : 144 - 95 = 49.
So the answer is : the area of the square is 49 units largee than the area of the square (C)
Answer:
2 units
Step-by-step explanation:
From the sides of the coordinate vertices PQ, you count how much coordinates on a graph it takes to get to one point as length.
Answer:
3
Step-by-step explanation:
<u>1) Find two corresponding lengths between the image and the pre-image</u>
Pre-image (bottom side) = 3 units
Image (bottom side) = 9 units
We can use any corresponding lengths for this step.
<u>2) Divide the length of the side from the image by the length of the side from the pre-image</u>
9 units ÷ 3 units
= 3
Therefore, the scale factor of the dilation is 3.
I hope this helps!
