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Leni [432]
3 years ago
5

I don’t understand question 4?

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0
Me either but its C.
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Solve for x: 4/x+4/x2-9=3/x-3
anzhelika [568]

Answer:

x =1/12(1-√(97) )

Step-by-step explanation:

4 0
3 years ago
I’ll give brainliest please help asap :D
USPshnik [31]
<h3>Answer:</h3><h3> C</h3><h3 /><h3>Step-by-step explanation:</h3><h3>It is C.</h3>

Thanks!

:)

Hope i helped

4 0
3 years ago
Cost of admission to a town fair was $8 for adults and $5 for children. If 206 people
tatiyna
I think 176 adult tickets were sold , sry if it’s wrong i’m kinda bad in math
7 0
3 years ago
What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)  

We know that, distance between two points P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right) is given by  

P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now,  

\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}

8 0
3 years ago
I need to solve this equation, when you answer i would like the steps on how you did it so that i can do problems like this one.
Alla [95]

Answer:

3(3x-1)

Step-by-step explanation:

3(2x-1)+3

3(2x-1x)

3(3x-1)

3(3x-1)

5 0
3 years ago
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