Hey there!
The answer is D. 1/5
An explanation is in the attached image below.
Hope this helps!
To solve this problem, we make use of the Binomial
Probability equation which is mathematically expressed as:
P = [n! / r! (n – r)!] p^r * q^(n – r)
where,
n = the total number of gadgets = 4
r = number of samples = 1 and 2 (since not more than 2)
p = probability of success of getting a defective gadget
q = probability of failure = 1 – p
Calculating for p:
p = 5 / 15 = 0.33
So,
q = 1 – 0.33 = 0.67
Calculating for P when r = 1:
P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3
P (r = 1) = 0.3970
Calculating for P when r = 2:
P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2
P (r = 2) = 0.2933
Therefore the total probability of not getting more than
2 defective gadgets is:
P = 0.3970 + 0.2933
P = 0.6903
Hence there is a 0.6903 chance or 69.03% probability of
not getting more than 2 defective gadgets.
Sammy made 6 baskets so whever mad 6*3 baskets or 18 is Jefferson . mult statement =6*3
Cassidy made x times as mitchel or 24=3x so the answer is 8
24/3=8
Jefferson made ____ times as many baskets as ____
you could use sammy or mitchell so if we use sammy
jeff made 3 times as many as sammy
18/6=3
sammy made twice the baskets as ____
sammy divided by 2 = person=6/2=3 and the thre person is mitchell so 6/2=3
BE and CD are parallel, so the triangles ABE and ACD are similar. Then the following relation holds:
AE/AD = AB/AC
10/(10 + 8) = x/(x + 6)
Solve for x :
10 (x + 6) = x (10 + 8)
10x + 60 = 18x
8x = 60
x = 60/8 = 7/5
