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Nataliya [291]
3 years ago
15

A rectangular tank that is 3 meters long, 4 meters wide and 6 meters deep is filled with a rubbing alcohol that has density 786

kilograms per cubic meter. assume that the tank is initially full, and that gravity is 9.8 meters per second squared. How much work is done pumping the liquid...
a. Out over the top of the tank?
b. Out of a spout 2meters above the top of the tank?
c. 2/3 of the liquid out over the top of the tank?
d. 2/3 of the liquid out of a spout two meters above the top of the tank?

Please include steps.
Thank You.
Mathematics
1 answer:
lawyer [7]3 years ago
4 0
Where did you get this from?
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Help me with #5 pleaseeeeeeeeeee
earnstyle [38]

Answer:

\angle 1 = 45 degrees

Step-by-step explanation:

Sum of 3 angles in a triangle is 180..

The angles given are:

60

7x + 12

1

So we sum to 180 and write:

60+7x+12+\angle 1=180\\72+7x+\angle 1=180\\7x+\angle 1=108

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

14x+9+\angle 1=180\\14x + \angle 1=171

Or we can write this as:

14x + \angle 1=171\\\angle 1 = 171 - 14x

We substitute this expression for Angle 1 into 1st equation we got and solve for x first,

7x+\angle 1 = 108\\7x+( 171 - 14x)=108\\-7x=-63\\x=9

Since x = 9, the angle "14x + 9" would be:

14(9) + 9 = 135

Hence Angle 1 would be:

\angle 1 + 14x + 9 = 180\\\angle 1 + 135 = 180\\\angle 1 = 45

6 0
2 years ago
Whats the asnwer for this question?
sergij07 [2.7K]

Answer:

C

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
what is the unknown number in sequence 2 in the chart? What rule can you write that relates sequence 2 to sequence 1
sergij07 [2.7K]
Answer C. The pattern is that each number in sequence 1 is being doubled to get the number in sequence 2, and 40*2=80
3 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
2 years ago
Liliana solved the equation below. When she tried to verify her answer, she realized she made an error.
katrin2010 [14]
It should be :
1/3(x + 18) = 7
1/3x + 6 = 7
1/3x + 6 - 6 = 7 - 6
1/3x = 1
x = 3
6 0
3 years ago
Read 2 more answers
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