I honestly don’t know what the answer is but I’m sorry
Answer:
C)
Step-by-step explanation:
Have a great day
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
The length and width of a rectangular field fully enclosed with 218 metes fencing are 63 meters and 46 meters respectively.
The perimeter of a rectangle is the sum of the whole four sides. Therefore, the perimeter of a rectangle is defined as follows:
where
l = length
w = width
perimeter = 218 meters
The length of the field is 17 meters longer than the width, w. Therefore, the length is defined as follows:
The length and the width can be calculated as follows:
218 = 2(l + w)
218 = 2(17 + w + w)
218 = 34 + 4w
218 - 34 = 4w
184 = 4w
divide both sides by 4
w = 184 / 4
w = 46 meters
length = 17 + 46
length = 63 meters
learn more on rectangle here: brainly.com/question/15989799?referrer=searchResul
