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LekaFEV [45]
3 years ago
7

Pay Periods a

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer:

¢42 per game

¢1.11 per minute

Step-by-step explanation:

Please refer to the attached image for explanations

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To rent a certain meeting room, a college charges a reservation fee of $18 and an additional fee $5 of per hour. The chemistry c
julsineya [31]

Answer:

You need the minimum cost for renting the meeting room given the following info

Reservation Fee = $18

Hourly Rate = $5

The renter wants to keep the cost below $58

So the cost will vary with the time, t you use the inequality below

5t + 18 ≤ 58

You can solve this to get that minimum

You can check you answer by graphing it.

I hope this helps!<3

3 0
3 years ago
Someone please help!​
umka21 [38]
Im not sure, when in doubt pick C
3 0
3 years ago
Each marble bag sold by Josh's Marble Company contains 7 yellow marbles for every 5 red marbles. If a bag has 25 red marbles, ho
elixir [45]
5 red : 7 yellow
25 red: ? Yellow

5 x 5 is 25 therefore the multiplier is 5
We multiply 7 by 5 which is 35

Therefore 24 red : 35 yellow

35 yellow marbles
8 0
3 years ago
If f(x) = x2, which of the following describes the graph of f(x - 1)? A. The graph of f(x - 1) is a horizontal shift of f(x) = x
pantera1 [17]

Answer:

A

Step-by-step explanation:

To understand this, we can look at the vertical & horizontal translations of a parabola of the form  f(x)=x^2

  • A vertically translated parabola has the form  f(x)=x^2+k, where k is the vertical shift upward when k is positive and vertical shift downward when k is negative.
  • A horizontally translated parabola has the form  f(x)=(x-a)^2, where a is the horizontal shift rightward when a is positive and horizontal shift leftward when a is negative.

When we replace x of the original function with (x-1), we have  f(x)=(x-1)^2. According to the rules, this means that the original function is shifted 1 unit right (horizontal shift).

Correct answer is A.

4 0
3 years ago
Read 2 more answers
Solve the inequality. 1/6w≥2.5
Viefleur [7K]

\dfrac{1}{6}w\geq2.5\qquad\text{multiply both sides by 6}\\\\\not6^1\cdot\dfrac{1}{\not6_1}w\geq6\cdot2.5\\\\\boxed{w\geq15}

7 0
3 years ago
Read 2 more answers
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