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Alika [10]
3 years ago
15

A cookie jar contains 6 chocolate chip cookies, 4 oatmeal cookies, 8 peanut butter cookies, and 2 sugar cookies. If a cookie is

pulled from the jar what is the probability that it is oatmeal or peanut butter?
Mathematics
2 answers:
Dmitry [639]3 years ago
7 0
The chances of getting a peanut butter cookie is higher than the probability of greeting oatmeal cookies??
Hitman42 [59]3 years ago
4 0

A. Rolling a die, where odd numbers represent sugar cookies and even numbers represent chocolate chip cookies.

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X over 3 equals 2 over 5
natali 33 [55]

Answer:

so

x = 6 over 5

Step-by-step explanation:

mark me brainliest if u have any doubt ask me

4 0
3 years ago
51 degrees 44 degrees 31 degrees 42 degrees 52 degrees 39 degrees and 55 degrees what are the average median and mode of these t
yarga [219]
Median = 44 mode= none
6 0
3 years ago
Which problem can we solve with 27 : 3?
N76 [4]

Answer:

La Tasha has 27 rabbit stickers. She splits the stickers

evenly among 3 pieces of paper. How many stickers

did La Tasha put on each piece of paper?​

Step-by-step explanation:

6 0
3 years ago
Each cone of the hourglass has a height of 12 millimeters. The total height of the sand within the top portion of the hourglass
Harman [31]

The solution would be like this for this specific problem:

Volume of a cylinder = pi * r^2 * h 

Volume of a cone = 1/3 * pi * r^2 * h 

Total Height = 47

Height of the cone = 12

Height of the cylinder = 35

If the top half is filled with sand, then:

volume (sand) = pi * 4^2 * 36

volume (cone) =  1/3 * pi * 4^2 * 12

Total volume = 1960.353816 cubic millimeters

353816 / (10 * pi) = 62.4 seconds.

It will take 62.4 seconds until all of the sand has dripped to the bottom of the hourglass.

7 0
3 years ago
I need help asap with this
tatyana61 [14]

Answer:

51°

Step-by-step explanation:

Given

<QPR = 39°

<PQR = 90° ( inscribed angle in semi circle)

Now

<QPR + <PQR + <PRQ = 180° { being sum of angles of triangle)

39° + 90° + <PRQ = 180°

<PRQ = 180° - 39° - 90°

<PRQ = 51°

Hope it will help :)

5 0
3 years ago
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