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natulia [17]
3 years ago
9

The number of customers in a store on the first day is represented by: (6x - 3) The number of customers on the second day is rep

resented by: (x - 1) Write an expression to find how many more customers visited the store on the first day.
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:the expression is 5x - 2

Step-by-step explanation:

The number of customers in a store on the first day is represented by: (6x - 3).

The number of customers on the second day is represented by: (x - 1)

An expression to find how many more customers visited the store on the first day would be the difference between the number of customers that visited the store on the first day and the number of customers that visited the store on the second day. The expression becomes

6x - 3 - (x - 1)

= 6x - 3 - x + 1

= 6x - x - 3 + 1

= 5x - 2

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3 years ago
Rewrite the equation in Ax+By=C form.<br><br> Use integers A, B, and C.<br><br> y+5=5(x-3)
Kaylis [27]

y+5=5(x-3)\\ y+5=5x-15\\ 5x-y=20

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3 years ago
Read 2 more answers
Compare and contrast the relative frequency for the whole table in part B with the two-way frequency table given in the activity
PIT_PIT [208]

The way to convert counts into relative frequencies in a Two Way Relative Frequency Table is to divide the count by the total number of items

<h3>What is a Frequency Table?</h3>

This refers to the depiction of the number of times in which an event occurs in the form of a table.

Hence, when a two-way frequency table is used, it shows the visual representation of the possible relationship between different sets of data.

Please note that your question is incomplete as you did not provide the frequency table needed and also the trends and generalizations to find, so a general overview was given.

Read more about frequency tables here:

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3 0
2 years ago
Data is collected to perform the following the hypothesis test:
nekit [7.7K]

Answer:

option f is right

Step-by-step explanation:

Given that data is collected to perform the following hypothesis test.

H_0: \mu = 5.5\\H_a: \mu >5.5

(right tailed test)

Sample mean = 5.4

p value = 0.1034

when p value = 0.1034 we normally accept null hypothesis.  i.e chances of null hypothesis true is  the probability of obtaining test results at least as extreme as the results actually observed during the test, assuming that the null hypothesis is correct

f) If the mean µ does not differ significantly from 5.5 (that is, if the null hypothesis is true), then the probability of obtaining a sample mean y as far or farther from 5.5 than 5.4 is .1034.

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3 years ago
Help with the 1st one and Second one.
gayaneshka [121]

132 feet per second

And

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Your welcome...

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