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ivanzaharov [21]
2 years ago
15

Use the matrix tool to solve the system of equations. Choose the correct

Mathematics
1 answer:
posledela2 years ago
5 0
4x-9y=2 this is the answer
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What is the value of a cube if the length of one side is 9 inches
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729 in ^3

Step-by-step explanation:

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Sandy’s Sandwich Shop has both inside and outside seating for customers. Last month, the restaurant had 4,668 customers altogeth
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51348

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4,668 x 11

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The figure below has a point marked with a large dot.
OleMash [197]

Therefore ,The marked point will now have the updated coordinates P' (2, 7).

<h3>Define Translation of Points on a Coordinate Plane.</h3>

When a figure is transferred from one area to another without altering its size, shape, or orientation, a translation takes place. If we know which way and how far the figure to be moved, we can draw the translation in the coordinate plane.

Here,

On an X-Y coordinate plane, a figure is plotted.

When translating a figure 7 units to the down, we must provide the coordinates of the indicated point in the original figure

"(x, y)" = "(x + m, y + n)"

In response to the query, we have

The specified point's coordinates are: P (5,4).

The new coordinates of the indicated spot after this figure is translated 6 units to the right will be -

P'( 5,4- 7) = P'(5, -3) (5, -3)

As a result, the designated point's new coordinates are P' (5, -3)

The new coordinates of the marked point will be - P'(5, -3)

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6 0
1 year ago
Find the relative minimum of
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

The max and min values exist where the derivative of the function is equal to 0. So we find the derivative:

y'=9x^2+28x-11

Setting this equal to 0 and solving for x gives you the 2 values

x = .352 and -3.464

Now we need to find where the function is increasing and decreasing.  I teach ,my students to make a table.  The interval "starts" at negative infinity and goes up to positive infinity.  So the intervals are

-∞ < x < -3.464           -3.464 < x < .352             .352 < x < ∞

Now choose any value within the interval and evaluate the derivative at that value.  I chose -5 for the first test number, 0 for the second, and 1 for the third.  Evaluating the derivative at -5 gives you a positive number, so the function is increasing from negative infinity to -3.464.  Evaluating the derivative at 0 gives you a negative number, so the function is decreasing from -3.464 to .352.  Evaluating the derivative at 1 gives you a positive number, so the function is increasing from .352 to positive infinity.  That means that there is a min at the x value of .352.  I guess we could round that to the tenths place and use .4 as our x value.  Plug .4 into the function to get the y value at the min point.

f(.4) = -48.0

So the relative min of the function is located at (.4, -48.0)

3 0
3 years ago
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