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Andreyy89
3 years ago
14

Last week you worked 24 hours, and earned $240.

Mathematics
2 answers:
valina [46]3 years ago
7 0

Answer:

Step-by-step explanation:240 : 24=10

Hourly rate is $10.00

Greeley [361]3 years ago
7 0

$10 an hour

First you divide 240 by 24 and your answer is 10;)

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What is the midpoint of a segment with endpoints at (−4, −8) and (8, 10)? A.(−6, −9) B.(−6, 1) C.(2, −9) D.(2, 1)
spayn [35]

\text{The formula of the midpoint of segment AB:}\\\\\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right).\\\\\text{We have the points}\ A(-4,\ -8)\ \text{and}\ B(8,\ 10).\ \text{Substitute:}\\\\x=\dfrac{-4+8}{2}=\dfrac{4}{2}=2\\\\y=\dfrac{-8+10}{2}=\dfrac{2}{2}=1\\\\Answer:\ \boxed{D.\ (2,\ 1)}

3 0
3 years ago
ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (
harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

<em>See the image in the attachment for the referred diagram.</em>

<em />

  • The two triangles, triangle AEC and triangle BDC are similar triangles.
  • Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

  • AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

  • Plug in the values

\frac{8.1}{5.4} = \frac{AE}{2.6}

  • Cross multiply

5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06

  • Divide both sides by 5.4

AE = \frac{21.06}{5.4} = 3.9 $ cm

<u>b. </u><u>Find the length of </u><u>AB:</u>

AB = AC - BC

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

  • Plug in the values

\frac{6.15}{BC} = \frac{8.1}{5.4}

  • Cross multiply

BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1

  • Thus:

AB = AC - BC

  • Substitute

AB = 6.15 - 4.1\\\\AB = 2.05 $ cm

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

Learn more here:

brainly.com/question/14327552

3 0
3 years ago
What is the solution of the equation? Eliminate any extraneous solutions √3x + 28 - 8 = x
Alecsey [184]
The answer to the solution is x=43+√249/2

I hope this helps.
6 0
3 years ago
0.8344 rounded to the nearest thousandth would be?
stiks02 [169]

Answer:

Look at the place after the thousandths, it is less than 5.

0.8344

So don't add +1 to the thousandths place.

Rounded to the nearest thousandths would be:

<h2>0.834</h2>

8 0
3 years ago
Read 2 more answers
The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a
Juliette [100K]

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{   }\times\text{  m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48  }\times\text{  100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}

Hence, there are 300 students.

a)

\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{  }\times\text{  300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72  students} \end{gathered}

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

percentage that read 4 books = 16%

36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

8 0
1 year ago
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