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diamong [38]
3 years ago
12

Find the difference. (4−5y)−2(3.5y−8)

Mathematics
2 answers:
nika2105 [10]3 years ago
5 0

Answer:

-4·(3y-5)

Step-by-step explanation:

MAVERICK [17]3 years ago
4 0

Answer:

-12y + 20

Step-by-step explanation:

First, you simplify each term:

apply the distributive property:

4 - 5y - 2 (3.5y) - 2 x -8

Multiply 3.5 by -2:

4 - 5y - 2 (3.5y) - 2 x -8

Multiply -2 by -8:

4 - 5y - 7y +16

Next, we simplify by adding terms:

Add 4 + 16:

-5y - 7y + 20

Subtract 7y from 5y:

-12y + 20

Hence the simplified form is -12y + 20

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jarptica [38.1K]

Here the solution in in picture.

6 0
3 years ago
It is impossible to slice a triangular pyramid with a plane and get a quadrilateral cross section.
Ksivusya [100]

Answer:

false

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Adam has $2.15 in nickels, dimes and quarters in his pocket. If the number of dimes is 4 less than the number of nickels, and 5
Alexus [3.1K]

Answer:

8 Dimes,12 Nickels, and 3 Quarters

Step-by-step explanation:

d= amount of dimes  n=amount of nickels  q=amount of quarters

You have to make formulas for the different variables. Since there are four more dimes than nickels so you have d+4=n. same thing with quarters but LESS so you would subtract d-5=q.

Then making the big picture;

Dimes have 10 cents Nickles have 5 cents, and Quarters have 25 cents. We do not know how many of each we have but we do know how much they are so when you add them together you would have to get the amount of money. That is  were the amount of each coin comes in so we have 10(d) for dimes 5(n) for nickles then 25(q) for quarters. We know the total of those is going to get 215 for the $2.15. This is how we get the big formula 10(d)+5(n)+25(q)=215.

Now we just plug things in 10(d)+5(d+4)+25(d-5)=215. Now we solve for D.

Distribute the 5 and 25   10d+5d+20+25d-125=215

Add common multiples   40d-105=215

Add 105 to both sides   40d=320

Divide 40 to both sides d=8

Now you have to figure out how many quarters and nickels you have just plug them into the other formulas;

n=d+4    n=8+4    n=12

q=d-5     q=8-5     q=3

You can ALWAYS check you answer by plug them into the "big picture"

10d+5n+25q=215   ~   10(8)+5(12)+25(3)=215  ~  80+60+75=215

3 0
3 years ago
Read 2 more answers
Am i gay tell me to me stragiot my phone number is 208 431 7721 A restaurant bill is $25, and a 20 percent tip should be given t
otez555 [7]

Answer:

25 dollars times 0.20

Step-by-step explanation:

7 0
3 years ago
A. Find the common factors of 12 and 20.
Alchen [17]

Answer:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

Step-by-step explanation:

a.) To find the common factors of 12 and 20:

First of all, let us find the factors of 12 and 20

12 = <em><u>2 </u></em>\times<em><u> 2</u></em> \times 3

20 = <em><u>2 </u></em>\times<em><u> 2</u></em> \times 5

The common factors are underlined above i.e. 2, 2.

2. The highest common factor between 12 and 20 is 2 \times 2 = <em>4</em>

-------------------------------------------

Workbooks are in packs of 25

Textbooks are in pack of 15

The school needs exactly same number of workbooks and textbooks.

And we have to find such least number.

This least number can simply be calculated by finding the LCM (Least Common Multiple).

LCM of two numbers p and q is the minimum number which is completely divisible by both the numbers p and q.

Let us find LCM of 25 and 15 using factorization method:

15 = 3 \times <em><u>5</u></em>

25 = 5 \times <em><u>5</u></em>

<em><u /></em>

The common part is considered only once:

So LCM =  3 \times 5 \times 5 = 75

Hence, number of packs of workbooks to be bought = \frac{75}{25} = 3

number of packs of textbooks to be bought = \frac{75}{15} = 5

So, the answer are:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

8 0
4 years ago
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