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lbvjy [14]
2 years ago
9

How does a food chain model energy flow ?

Biology
1 answer:
coldgirl [10]2 years ago
4 0
Food chains model energy flow through an ecosystem. Producers pump energy into an ecosystem from an environmental source, and this energy is then passed from one organism to the next.
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Which of the following could result in the extinction of a species?
mylen [45]

Increased population size will result in the extinction of a species of organisms.

<h3>What is Extinction?</h3>

This is defined as the dying out or disappearance of species as a result of various factors.

When population size increases, it leads to unavailability of food and reduction of species due to starvation and death.

Read more about Extinction here brainly.com/question/1027555

#SPJ1

7 0
1 year ago
In dogs, wire hair is due to a dominant gene (W), smooth hair id due to its recessive allele.a. If a homozygous wire-haired dog
Vsevolod [243]

Answer:

a) All the offspring produced would be a heterozygous in the first generation (F1 generation) with genotype: Ww, Ww, Ww, and Ww. Since wire hair is dominant, all would be wired haired.

b) In the F2 (second generation), we breed the heterozygous offspring from the F1 generation together (Ww x Ww). This will produce 3:1 ratio of dominant:recessive phenotypes having 3/4 of the offspring wire-haired (1/4 WW homozygotes and 1/2 Ww heterozygotes) and 1/4 will be smooth-haired (ww). Also the genotype would have the ratio 1:2:1 (i.e 1 homozygote WW, 2 heterozygote Ww and 1 smooth hair)

c) the chances of producing a smooth-haired pup is 1/4, and the chances of producing a wire-haired pup are 3/4.

d) Therefore, 1/2 of the offspring will have the genotype Ww and be wire-haired, and 1/2 of the offspring will be ww and be smooth-haired.  Also the phenotype ratio is 1:1 (1/2 is heterozygote wired hair and 1/2 is smoth haired)

Explanation:

Since the wire hair is the dominant gene (W) and smooth hair (w) is the recessive allele

a)  If a homozygous wire-haired dog is mated with a smooth-haired dog, All the offspring produced would be a heterozygous in the first generation (F1 generation) with genotype: Ww, Ww, Ww, and Ww. Since wire hair is dominant, all would be wired haired.

b) In the F2 (second generation), we breed the heterozygous offspring from the F1 generation together (Ww x Ww). This will produce 3:1 ratio of dominant:recessive phenotypes having 3/4 of the offspring wire-haired (1/4 WW homozygotes and 1/2 Ww heterozygotes) and 1/4 will be smooth-haired (ww). Also the genotype would have the ratio 1:2:1 (i.e 1 homozygote WW, 2 heterozygote Ww and 1 smooth hair)

c) If two wire-haired dogs produce a smooth-haired pup, that means that both parents must be heterozygotes (Ww) having a pair of dominant W allele and recessive w allele to pass on to the offspring. Therefore, if these two dogs were to mate again (Ww x Ww), the chances of producing a smooth-haired pup is 1/4, and the chances of producing a wire-haired pup are 3/4.

d) If the mother of the wire-haired male was smooth-haired, that means that the recessive allele w had been passed on to the male making the male a   heterozygote (Ww). When this male mates with a smooth-haired female (ww), the cross is Ww x ww. Therefore, 1/2 of the offspring will have the genotype Ww and be wire-haired, and 1/2 of the offspring will be ww and be smooth-haired.  Also the phenotype ratio is 1:1 (1/2 is heterozygote wired hair and 1/2 is smoth haired)

8 0
2 years ago
Each lung is fed oxygen by a separate bronchus. Please select the best answer from the choices provided. T F
marysya [2.9K]
Yes it is absolutely true that each lung is fed oxygen by a separate bronchus. There are actually two lungs and two bronchi. Each of the two lungs are safeguarded by the two ribcages as they are placed within the rib cages. The lungs actually consists of elastic sacs that contract and expand for taking in and releasing air. This way oxygen is passed into the blood and carbon dioxide is taken out from the blood and passed out. This is also the main function of the lungs.
5 0
3 years ago
Read 2 more answers
Which of the following statements about excision repair is correct?
maxonik [38]

Answer:

a. True, b. False, c.True, d. True

Explanation:

a. Base excision repair is started by a DNA glycosylase  that recognizes the changes and removes the altered base by cleavage of the glycosidic bond binding the base and the deoxyribose sugar together.

b. Nucleotide excision repair works by a cut-and patch mechanism that removes their heavy lesions, including pyrimidine dimers and nucleotides . Endonucleases are responsible for the lesion of the damaged strand.

c. Nucleotide excision repair  is initiated by the proteins namely UvrA, UvrC, and UvrB in Escherichia coli.

-UvrD (helicase II) later removes the damaged strand

-DNA polymerase I (PolI) fills in the resulting gap.

d. DNA glycolases removes the damaged nitrogenous base.

-It leaves the sugar-phosphate backbone intact and thus creating an  apurinic/apyrimidinic site, which is commonly referred to as an AP site.

e. Xeroderma pigmentosum complementation group A(XPA)

-This is an essential protein in the nucleotide excision repair pathway.

- It helps to make a pre-incision complex along with other proteins.                

4 0
3 years ago
How long can a healthy ecosystem remain stable? A. five to ten years B. one year C. hundreds or thousands of years D. about fift
ANTONII [103]

Answer:

D.  Sorry if it is wrong.

Explanation:

7 0
3 years ago
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