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Andru [333]
3 years ago
9

2x+5d-9×2c+844+233+2×+78d​

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
5 0

Answer:

−18c+83d+4x+1077

Step-by-step explanation:

combine all like terms

(2x+2x=4x)

(5d+78d=83d)

(-9*2c=-18c)

(1077=844+233)

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Sarah walks to school, 1.5 miles in 30 minutes. what is the snswer to this
nevsk [136]

Answer: 3 mi/h

Step-by-step explanation:

Here we have to find the speed V at which Sarah walks to school, knowing the distance d she has walked and the time t she expends.

So, in this case we can use the following equation:

V=\frac{d}{t}

Where:

d=1.5 mi

t=30 min \frac{1 h}{60 min}=0.5 h

Solving:

V=\frac{1.5 mi}{0.5 h}

V=3 mi/h This is Sarah's speed

5 0
3 years ago
Find a fraction in between 21/34 and 34/55
sashaice [31]

Answer:

A fraction between that is 2311/3740

Step-by-step explanation:

This is because the denominator is simplified into one number and the fraction is taken from there.

3 0
3 years ago
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In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?
vichka [17]

Answer:

x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-10 and c=6

Putting values in the quadratic formula

x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}

So, x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

3 0
3 years ago
Read 2 more answers
The following graph shows a proportional relationship.
Molodets [167]

Answer:

4

Step-by-step explanation:

because, if y = 4 and x = 1 then it would be 4/1 or 4 just simplify.  

Y/X --- Y = 4 --- X = 1 ---- that makes 4/1 or 4

5 0
3 years ago
A company that explores for oil in the ocean is considering two new sites, A and B. The exploration will take the entire year. T
Lelu [443]

Answer:

Step-by-step explanation:

Hello!

There are two sites A and B,

Be the events A: finding oil in site Awith probability P(A)= 0.6

and B: finding oil in B with probability P(B)= 0.84

A and B are independent (there cannot be found oil of A in B and vice versa)

Remember, two events are independent when the occurrence of one of them doesn't modify the probability of occurrence of the other one in two repetitions of the experiment.

1) Find the probability that oil is found at both sites (round your answer to 2 decimal places)

If there is oil in both sites then event A and B are observed, symbolically:

P(A∩B)

Since both events are independent, the probability of the intersection of both events is equal to the product of each probability so:

P(A∩B)= P(A)*P(B)= 0.6*0.84= 0.504

2) Find the probability that oil is found at only one of the sites (round your answer to 2 decimal places)

In this case, you have two situations in which the statement can occur:

> "finding oil in A" and "not finding oil in B"

-or-

> "not finding oil in A" and "finding oil in B"

Be A' the complementary event of A, i.e. "not finding oil in region A", with probability P(A')= 1 - P(A)= 1 - 0.6= 0.4

And B' the complementary event of B, i.e. "not finding oil in region B", with probability P(B')= 1 - P(B)= 1 - 0.84= 0.16.

You can symbolize these two possible occurrences as:

Remember that "and" indicated intersection between two events, symbolized ∩, and "or" indicates the union between two events, symbolized ∪.

P((A∩B')∪(A'∩B))= P(A∩B') + P(A'∩B)= [P(A)*P(B')]+[P(A')*P(B)]= (0.6*0.16)+(0.4*0.84)= 0.432

I hope it helps!

7 0
3 years ago
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