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3 years ago

I need help with 3-4 quick

Mathematics

1 answer:

Agata [3.3K]3 years ago

6 0

3-4 = -1

Hope this helps!

:)

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6 people will attend a lunch. 2 cans of juice should be provided per person. Determine the total number of cans of juice require

kirza4 [7]

Answer:

Step-by-step explanation:

If 6 people attend lunch and they get 2 cans of juice each then there is 12 cans of juice.

A=2

B=2

C=2

D=2

E=2

F=2

Total cans of juice=12

4 0

3 years ago

Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10

damaskus [11]

Answer:

Step-by-step explanation:

set

$f(x,y)=x+y\\$

constrain:

$g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10$

Partial derivatives:

$f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2$

Lagrange multiplier:

$grad(f)=a*grad(g)+b*grad(h)\\$

$\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]$

4 equations:

$1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10$

By solving:

$a=4/9\\b=-2/27\\x+y=4$

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

$x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4$

The maximum is 4

6 0

3 years ago

Please help right now please

const2013 [10]

Answer:

A or 24

Step-by-step explanation:

In PEMDAS you do the steps from left to right in the name.

So first, you do 3 * x and x = 6 so 3 * 6 which is 18.

then 18 + y and y = 8 so 26

26 minus 2 is 24.

Hope this helped~ ^-^

4 0

3 years ago

the figure at the right shows the dimensions of the garden in Marissa's back yard. What is the area of the garden?

vodka [1.7K]

The area of the garden is 74 square feet

<h3>How to determine the area of the garden?</h3>

The complete question is added as an attachment

From the attached figure, we have the following shapes and dimensions:

Rectangle: 10 by 5 feet
Trapezoid: Bases = 10 and 6; Height = 3

The rectangular area is

A1 = 10 * 5

Evaluate

A1 = 50

The area of the trapezoid is

A2 = 0.5 * Sum of parallel bases * height

This gives

A2 = 0.5 * (10 + 6) * 3

Evaluate

A2 = 24

The total area is

Total = A1 + A2

This gives

Total = 50 + 24

Evaluate

Total = 74

Hence, the area of the garden is 74 square feet