Not of Bernoulli type, but still linear.
There's no need to find an integrating factor, since the left hand side already represents a derivative:
![\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=(1+x^2)\dfrac{\mathrm dy}{\mathrm dx}+2xy](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5B%281%2Bx%5E2%29y%5D%3D%281%2Bx%5E2%29%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%2B2xy)
So, you have
![\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=4x^2](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5B%281%2Bx%5E2%29y%5D%3D4x%5E2)
and integrating both sides with respect to
yields
They both are 180 degrees.
One possible difference is that a straight angle is just a single angle measuring 180 degrees, while a linear pair supplementary angle are pairs of adjacent angles that add up to 180 degrees.
437 + 356= 793
ANSWER: 793
Hope this helps! :)
Answer:
3 oz
Step-by-step explanation:
You have to divide 6 by 2 and you'll get the answer.
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
