How to find the equation of a line that is parallel and passes through a point
1 answer:
Answer:
Step-by-step explanation:
Parallel line have the same slope. Put the reference line is y=mx+b format. m will be the slope. A parallel line must have the same m. Example:
y=2x+5 has a slope of 2 and a y-intercept of 5 (the value of y when x is 0). Any line witrh the same slope will be parallel. So with can write y=2x+b, where we'll change the y-interecpt so the the lines don't overlap. Once we know the parallel line must be y = 2x+b, we can enter the known point, e.g., (3,14), and calculate b:
y=2x+b
14=2*3+b
14=6+b
b=8
The parallel line to y=2x+5 is y=2x+8: It is parallel and goes through the point (3,14).
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Answer:
P' = (1, 1)
Step-by-step explanation:
When <u>rotating</u> a point 180° counterclockwise <u>about the origin</u> (0, 0), the rule is: (x, y) → (-x, -y)
So the x and y values simply become <u>negative</u>.
Therefore:
P = (-1, -1) → P' = (-(-1), -(-1)) = (1, 1)
Learn more about transformations here:
