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strojnjashka [21]
3 years ago
14

What is the correct answer?

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
The third one down is the correct answer. (-55 and 1)
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In a survey 9/25 students ride the bus and 19/50 walk to school. What fraction of students ride the bus or walk?
san4es73 [151]
Well since 19/50 can't be simplified you have to double 9/25 which is 18/50 so then add 18 + 19 = 37 So 18/50 + 19/50 = 37/50 so 37/50 of the students ride the bus or walk to school.
7 0
3 years ago
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If the pet store had 10 more birds the number of dogs would be double the number of birds what numbers should be on the scale
frosja888 [35]
If there were 10 dogs then there would be 20 birds
4 0
3 years ago
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Paula a college student earned $3,600 one summer during the following semester she spent $2500 for tuition $650 for rent and $43
Fed [463]
The fraction you are looking for is expenses/earnings 

So (2500+650+434)/3600
=224/225 

If you want to turn this into a percentage just multiply by 100, to give you 99.56%.
3 0
3 years ago
Andrew is two years older than Beatrice, and Chris is three years younger than Beatrice. The product of Andrew's age and Chris'
stich3 [128]

Answer:

9

Step-by-step explanation:

A = B + 2

C = B - 3

A x C = 66

A = Andrew

C = Chris

B = Beatrice

Multiply A and c together

(B + 2) x (b - 3)

b^2 - 3b + 2b - 6

b^2 -b - 6 = 66

b^2 - b - 72 = 0

factors of -72b^2 that add up to - b are -9b + 8b

b^2 + 8b -9b - 72

b (b + 8) -9(b + 8)

b = 9 or - 8

b = 9

5 0
3 years ago
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
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