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Vikentia [17]
3 years ago
13

HELP!!!

Mathematics
1 answer:
zubka84 [21]3 years ago
3 0

Answer:

multiply by 6

Step-by-step explanation:

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4 0
3 years ago
A garbage container is to be constructed out of 400 ft2 of material. The vessel will have a square base and an open top. Find th
sveticcg [70]

Answer:

  11.547 ft wide by 5.774 ft high

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Step-by-step explanation:

Volume is maximized for a given area by having the area of a pair of opposite sides equal the area of the bottom. That means the overall area of the container is 3 times the area of the bottom. Then the square bottom will have a width of ...

  w = √(400/3) ≈ 11.547 . . . feet

The height is half that, so is ...

  h = w/2 = 11.547/2 ≈ 5.774 . . . feet

The capacity is then ...

  w²h = (11.547 ft)²(5.774 ft) = 769.800 ft³

The container is 11.547 ft wide by 5.774 ft high. It has a capacity of 769.800 cubic feet.

_____

You want to maximize w^2h subject to w^2 + 4wh = 400. Solving the constraint equation for h, we get h = (400 -w^2)/(4w) and the volume we want to maximize can be written as ...

  V = w(400-w^2)/4

This will be an extreme when dV/dw = 0, so we want to solve ...

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Step-by-step explanation:

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