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Travka [436]
3 years ago
5

Solve this problem what is the answer x=4.7+8.3

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0
X= 13 would be the answer
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Kareen correctly answered 85% of the questions on his math test. If he answered 34
Levart [38]

Answer:

40

Step-by-step explanation:

6 0
3 years ago
Help Please!!!!!!
Vanyuwa [196]

Answer:

centre = (2, - 1), radius = 6

Step-by-step explanation:

Rearrange the equation by placing the x and y terms together and adding 31 to both sides

Given

x² + y² - 4x + 2y - 31 = 0, then

x² - 4x + y² + 2y = 31

Use the method of completing the square

add ( half the coefficient of the x/y term )² to both sides

x² + 2(- 2)x + 4 + y² + 2(1)y + 1 = 31 + 4 + 1

(x - 2)² + (y + 1)² = 36

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r the radius

compare to (x - 2)² + (y + 1)² = 36, then

centre = (2, - 1) and r = \sqrt{36} = 6

3 0
3 years ago
Ram noticed three students used 1 2/10 dm of tape.what was the total used for three students???
OLga [1]

Answer:

18/5

Step-by-step explanation:

<em>From my understanding, this is 1 whole 2 upon 10</em>

<u>Step 1: Convert mixed fraction into fraction</u>

<em>Multiply whole number by denominator: 1 x 10 = 10</em>

<em>Add numerator: 10 + 2 = 12</em>

<em>Write the result as the numerator and use the same denominator.</em>

12/10

<u>Step 2: Find the total tape used</u>

<em>From my understanding, each student used 12/10 of the tap</em>

<em>So 3 students used: 12/10 x 3 =</em> 18/5

Therefore, the total tape used for three students was 18/5.

!!

7 0
3 years ago
PLEASE HELP FAST!
ollegr [7]

Given two functions are

f(x) = 2 cos(x)

g(x) = 3 sin(x+ \pi)

We know that the maximum value of cos x and sin x is always 1

y= maximum of cos = 1

y= maximum of sin =1

f(x) = 2 cos(x)

y= 2 (max of cos) = 2(1) = 2

g(x) = 3 sin(x+ \pi)

y= 3 (max of sin) = 3(1) = 3

g(x) = 3 sin(x+ \pi) has the maximum value.

5 0
3 years ago
In a group of 60 students, 18 students take algebra i, 20 students take algebra ii, and 10 students take both subjects. how many
nadya68 [22]

Answer:

  32

Step-by-step explanation:

The number that take algebra i includes those who take both subjects, as does the number taking algebra ii. Then the number taking algebra i alone is ...

   18 -10 = 8 . . . . . take only algebra i

So the number taking any kind of algebra is ...

  20 + 8 = 28

and the number not taking either subject is ...

  60 -28 = 32 . . . not taking either subject

8 0
3 years ago
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