Answer:
40
Step-by-step explanation:
Answer:
centre = (2, - 1), radius = 6
Step-by-step explanation:
Rearrange the equation by placing the x and y terms together and adding 31 to both sides
Given
x² + y² - 4x + 2y - 31 = 0, then
x² - 4x + y² + 2y = 31
Use the method of completing the square
add ( half the coefficient of the x/y term )² to both sides
x² + 2(- 2)x + 4 + y² + 2(1)y + 1 = 31 + 4 + 1
(x - 2)² + (y + 1)² = 36
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r the radius
compare to (x - 2)² + (y + 1)² = 36, then
centre = (2, - 1) and r =
= 6
Answer:
18/5
Step-by-step explanation:
<em>From my understanding, this is 1 whole 2 upon 10</em>
<u>Step 1: Convert mixed fraction into fraction</u>
<em>Multiply whole number by denominator: 1 x 10 = 10</em>
<em>Add numerator: 10 + 2 = 12</em>
<em>Write the result as the numerator and use the same denominator.</em>
12/10
<u>Step 2: Find the total tape used</u>
<em>From my understanding, each student used 12/10 of the tap</em>
<em>So 3 students used: 12/10 x 3 =</em> 18/5
Therefore, the total tape used for three students was 18/5.
!!
Given two functions are
f(x) = 2 cos(x)
g(x) = 3 sin(x+
)
We know that the maximum value of cos x and sin x is always 1
y= maximum of cos = 1
y= maximum of sin =1
f(x) = 2 cos(x)
y= 2 (max of cos) = 2(1) = 2
g(x) = 3 sin(x+
)
y= 3 (max of sin) = 3(1) = 3
g(x) = 3 sin(x+
) has the maximum value.
Answer:
32
Step-by-step explanation:
The number that take algebra i includes those who take both subjects, as does the number taking algebra ii. Then the number taking algebra i alone is ...
18 -10 = 8 . . . . . take only algebra i
So the number taking any kind of algebra is ...
20 + 8 = 28
and the number not taking either subject is ...
60 -28 = 32 . . . not taking either subject