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3 years ago

How to convert an improper fraction into a mixed number

Mathematics

2 answers:

Reptile [31]3 years ago

8 0

Answer:

Step-by-step explanation:

ollegr [7]3 years ago

3 0

Https://www.wikihow.com/Convert-Improper-Fractions-Into-Mixed-Numbers

that should help

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If N = 34, what is 7 - N?

Gre4nikov [31]

7 - N (replace N with 34)

7 - 34

- 27

The answer is - 27

4 0

4 years ago

Can someone help me solve this IXL Problem

Tju [1.3M]

The answer is 42 because that is half of 84 and 31 of the muffins were banana which is half of 62

4 0

4 years ago

Read 2 more answers

The velocity function, in feet per second, is given for a particle moving along a straight line. Find (a) the displacement and (

AveGali [126]

Answer:

(a) 2 feet.

(b) 2 feet.

Step-by-step explanation:

We have been given that the velocity function $v(t)=\frac{1}{\sqrt{t}}$ in feet per second, is given for a particle moving along a straight line.

(a) We are asked to find the displacement over the interval $1\leq t\leq 4$ .

Since velocity is derivative of position function , so to find the displacement (position shift) from the velocity function, we need to integrate the velocity function.

$\int\limits^b_a {v(t)} \, dt$

$\int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt$

$\int\limits^4_1 {\frac{1}{t^{\frac{1}{2}}} \, dt$

$\int\limits^4_1 t^{-\frac{1}{2}} \, dt$

Using power rule, we will get:

$\left[\frac{t^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}}\right] ^4_1$

$\left[\frac{t^{\frac{1}{2}}}{\frac{1}{2}}}\right] ^4_1$

$\left[2t^{\frac{1}{2}}\right] ^4_1$

$2(4)^{\frac{1}{2}}-2(1)^{\frac{1}{2}}=2(2)-2=4-2=2$

Therefore, the total displacement on the interval $1\leq t\leq 4$ would be 2 feet.

(b). For distance we need to integrate the absolute value of the velocity function.

$\int\limits^b_a |{v(t)|} \, dt$

$\int\limits^4_1 |{\frac{1}{\sqrt{t}}}| \, dt$

Since square root is not defined for negative numbers, so our integral would be $\int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt$ .

We already figured out that the value of $\int\limits^4_1 {\frac{1}{\sqrt{t}}} \, dt$ is 2 feet, therefore, the total distance over the interval $1\leq t\leq 4$ would be 2 feet.

7 0

3 years ago

What is the true meaning of absolute value?

Rzqust [24]

Answer:

Change the value from negative to positive

Change the value from positive to positive

Step-by-step explanation:

It is very simple

Any number's absolute value should be positive

Let's say absolute value of 3 - >answer is 3

But absolute value of - 3 - > is also 3