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Julli [10]
3 years ago
9

Which value makes -1/2x-8<1 true A.-4 B.-20 C.3

Mathematics
1 answer:
Romashka [77]3 years ago
5 0
The value that makes this true is a
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Place value
s344n2d4d5 [400]

Expanded Notation:

A. 654.362 = (6x100) + (5x10) + (4x1) + (3x0.1) + (6x0.01) + (2x0.001)

B. 125.384 = (1x100) + (2x10) + (5x1) + (3x0.1) + (4x0.01) + (8x0.001)

8 0
3 years ago
Read 2 more answers
Using elimination (combination), which variable will be eliminated first? 5x-y=-21x+y=-3
stiks02 [169]

Answer:

Option B) The variable Y will cancel out first.

Step-by-step explanation:

we have

5x-y=-21 ----> equation A

x+y=-3 ----> equation B

Solve by elimination

Adds equation A and equation B

5x-y=-21

x+y=-3

--------------

5x+x=-21-3 ----->variable y will be eliminated first

6x=-24

x=-4

7 0
3 years ago
What is the equation, in slope-intercept form, of the line that passes through (0, −2) and has a slope of −3?
Julli [10]

Answer:

y= -3x-2

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).
inna [77]

Answer:

\huge{ \fbox{ \sf{ \: ( \: 3 \: ,  \:  - 1 \: )}}}

Step-by-step explanation:

\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}

\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and  \: B(-2,-8) \: be \: (x2 \:, y2)}}

\underline{ \sf{Finding \: the \: midpoint}}

\boxed{ \rm{Midpoint \:  =  \: ( \frac{x1 + x2}{2}  \: ,  \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{8 + ( - 2)}{2}  \: ,  \:  \frac{6 + ( - 8)}{2} )}}

\mapsto { \sf{Midpoint = ( \frac{8 - 2}{2}  \: ,  \:  \frac{6 - 8}{2} }})

\mapsto{ \sf{Midpoint = ( \frac{6}{2}  \: ,  \:  \frac{ - 2}{2}) }}

\mapsto{ \sf{Midpoint = (3 \: \:  ,   - 1)}}

Hope I helped!

Best wishes!! :D

~\sf{TheAnimeGirl}

5 0
3 years ago
Find: (4y – 5) (3y - 7)
Pachacha [2.7K]
I did it digitally on my iPad hope it helps please mark me brainliest

8 0
2 years ago
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