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4vir4ik [10]
3 years ago
12

What is the approximate area that is shaded blue?

Mathematics
2 answers:
weeeeeb [17]3 years ago
7 0
The answer to this question is c i think
Darya [45]3 years ago
6 0
^yeah I got the same answer it should be C.
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The null hypothesis for an ANOVA is that all treatments/samples come from populations with the same mean. The alternative hypoth
LenKa [72]

Answer:

Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have n groups and we want to check if the population means are equal, th best way to check this it's with an ANOVA test.

The hypothesis for this case are:

Null hypothesis: \mu_{1}=\mu_{2}=\dots =\mu_{n}

Or in words:

Null hypothesis: All treatments/samples come from populations with the same mean

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=1.2,\dots ,n

Or we can say:

Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others

8 0
3 years ago
Rachel has a bag of fruit that has a mass of 50 hectograms. Rachel converts this mass to centigrams. Her work is shown below.
Alinara [238K]

Answer:

She should have multiplied by 10,000

Step-by-step explanation:

Given table:

\begin{array}{| c | c |}\cline{1-2} \sf kilo & 1,000 \\\cline{1-2} \sf hecto & 100 \\\cline{1-2} \sf deka & 10 \\\cline{1-2} \sf unit & 1 \\\cline{1-2} \sf deci & 0.1 \\\cline{1-2} \sf centi & 0.01 \\\cline{1-2} \sf milli & 0.001 \\\cline{1-2}\end{array}

To find the conversion rate:

\sf \dfrac{hecto}{centi}=\dfrac{100}{0.01}=10000

Therefore, 1 hectogram = 10,000 centigrams

So when converting hectograms to centigrams, multiply the mass by 10,000.

⇒ 50 hg × 10,000 = 500,000 centigrams

Rachel's error was that she should have multiplied by 10,000.

7 0
2 years ago
Read 2 more answers
Alice is riding the train to her job in Paris, France. She accidentally purchased a ticket for zone 4, but she is
stepan [7]

Answer:

3005 euro is the answer

7 0
2 years ago
PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!​
KonstantinChe [14]

Answer:

b.  \displaystyle \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle H(x) = \sqrt[3]{F(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. Rewrite function [Exponential Rule - Root Rewrite]:                                      \displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}
  2. Chain Rule:                                                                                                        \displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]
  3. Basic Power Rule:                                                                                             \displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)
  4. Simplify:                                                                                                             \displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}
  5. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}
  2. Substitute in function values:                                                                          \displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}
  3. Exponents:                                                                                                        \displaystyle H'(5) = \frac{6}{3(4)}
  4. Multiply:                                                                                                             \displaystyle H'(5) = \frac{6}{12}
  5. Simplify:                                                                                                             \displaystyle H'(5) = \frac{1}{2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0
3 years ago
I’ll mark Brainiest?
Usimov [2.4K]
The answer is D. Group =2
8 0
3 years ago
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