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Sophie [7]
2 years ago
8

Larry graphs the inequality x less-than negative 5 using the steps below. Step 1: Draw a number line, and place an open circle a

t –5. A number line going from negative 10 to 0. An open circle is at negative 5. Step 2: Shade to the left of –5 to represent less than –5. A number line going from negative 10 to 0. An open circle is at negative 5. Everything to the left of the circle is shaded. Step 3: Check work by substitution. x = negative 5 Negative 5 less-than negative 5 False Larry concludes that he must have shaded the number line in the wrong direction. Which best describes the situation? Larry’s graph is incorrect. He should have used a closed circle at –5. Larry’s graph is incorrect. He should have shaded to the right of –5 because the numbers less than –5 are to the right of –5. Larry’s graph is correct. He should have checked his work using a number to the left of –5. Larry’s graph is correct. He should have checked his work using a number to the right of –5.
Mathematics
2 answers:
Yakvenalex [24]2 years ago
5 0

Answer:

<h2>YOUR CORRECT ANSWER'S (D.)</h2>

Step-by-step explanation:

nataly862011 [7]2 years ago
5 0

Answer:

<h2>d</h2>

Step-by-step explanation:

<h3><u>i took the test</u></h3>
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The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu
AURORKA [14]

Answer:

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21        x2`= 27

n1=  10       n2= 14

s1= 5.6       s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27)  +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 <  ( 6 )  +2.11*2.111

6- 4.4521 < u1-u2 <  ( 6 )  +5.294

- 1.5479 < u1-u2 <  10.4521

The confidence Interval is [- 0.7053  10.4521]

a: The  hypotheses  are

H0: μ1=μ2    against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f  t > 2.508 and  t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`)  /√s1²/n1 + s2²/n2

t= (21-27)  /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

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3 years ago
Does this graph show a function? Explain how you know.
marin [14]
Answer is (a.)
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6 0
2 years ago
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Answer:

The kitchen drawing is 48 millimeters long.

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Ist amount paid = $1500
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I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
R = I /(PT)  R = 500 / (4500*5/6)
R = (500*6) / (4500*5)
R = 0.1333..
R ≈ 13.33 %  per annum.

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The rental rate for a cement mixer has a flat rate of $40 plus $20 for each day of the rental. The graph shows points representi
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Answer:

Step-by-step explanation:

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x-number of days

20 is the slope

40-flat rate and the y-intercept is at (0,40)

4 0
2 years ago
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