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Sophie [7]
3 years ago
8

Larry graphs the inequality x less-than negative 5 using the steps below. Step 1: Draw a number line, and place an open circle a

t –5. A number line going from negative 10 to 0. An open circle is at negative 5. Step 2: Shade to the left of –5 to represent less than –5. A number line going from negative 10 to 0. An open circle is at negative 5. Everything to the left of the circle is shaded. Step 3: Check work by substitution. x = negative 5 Negative 5 less-than negative 5 False Larry concludes that he must have shaded the number line in the wrong direction. Which best describes the situation? Larry’s graph is incorrect. He should have used a closed circle at –5. Larry’s graph is incorrect. He should have shaded to the right of –5 because the numbers less than –5 are to the right of –5. Larry’s graph is correct. He should have checked his work using a number to the left of –5. Larry’s graph is correct. He should have checked his work using a number to the right of –5.
Mathematics
2 answers:
Yakvenalex [24]3 years ago
5 0

Answer:

<h2>YOUR CORRECT ANSWER'S (D.)</h2>

Step-by-step explanation:

nataly862011 [7]3 years ago
5 0

Answer:

<h2>d</h2>

Step-by-step explanation:

<h3><u>i took the test</u></h3>
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kumpel [21]

Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

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\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

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