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natulia [17]
4 years ago
5

Help please when I do the guadratic equation I’m doing something wrong

Mathematics
1 answer:
AnnZ [28]4 years ago
8 0

Answer:

Graph A

Step-by-step explanation

The problem: y=2x^2+8x+3

1) You will need to determine the direction of the parabola, If a > 0 then the parabola opens upward, if a < 0 then the parabola opens downward.

2) If when doing this you get an imaginary solution, you would have no x intercepts. The first thing you need to do is find the x intercepts, you can do this by plugging in 0 for y, so this would give you 0=2x^2+8x+3. Once you have this you start by subtracting 3 from both sides, dividing 8 from both side, etc. (If you would like me to elaborate don't hesitate to ask!)

3) To find the graphs y intercept you plug in 0 for x, which gives you y=2(0)^2+8(0)+3, you do the same thing you did during the previous step for y. (Once again, I am willing to elaborate further if you need!)

4) You then need to find the vertex (h,k)

To find h: h= -b/2a

To find k: k = a(h)2 + b(h) + c

5) Once you've worked through this you can graph the point!

Hope this helped!

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wel

Answer:

m∠A ≈ 43°

m∠B ≈ 55°

mBC ≈ 20

Step-by-step explanation:

Law of Sines: \frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Step 1: Find m∠B

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Step 2: Solve for ∠B

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Step 3: Find m∠A

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m∠A = 42.962°

Step 4: Find BC

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Step 5: Solve for BC

29sin42.962° = BCsin82°

BC = 29sin42.962°/sin82°

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