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A jar has 16 marbles, 10 green, 2 blue, 4 red. what is the probability of randomly choosing a red marble then without putting it

marta [7]

The probability of drawing a red marble and then a green marble is:

P = 1/6.

<h3>How to find the probability?</h3>

In the jar we have a total of 16 marbles, such that:

10 are green.
2 are blue
4 are red.

First, the probability of getting a red marble is give by the quotient between the number of red marbles and the total number of marbles:

p = 4/16 = 1/4

Now we need to draw a green one, the probability is computed in the same way, but this time there are 15 marbles, because we already took one.

q = 10/15

The joint probability (first drawing red, then green) is given by the product between the individual probabilities:

P = p*q = (1/4)*(10/15) = 10/60 = 1/6

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

8 0

1 year ago

Please help this is due in 10 minutes!!!!!!

Sergio039 [100]

Answer:

Step-by-step explanation:

you just gotta add all the side-lengths together and consider each grid square as 10 instead of 1.

so 70 + 40 + 20 + 60 + 20 + 40 i believe.

this all equals 250.

ask your teacher if its a type, because there's no 250 on there. grab a calculator or something as proof.

3 0

2 years ago

Would someone help me 2/3 2/1 8/9 7/9 breast to least

Tema [17]

Answer:

First of all, it's the Greatest to least! Second of all, 2/1, 8/9, 7/9, and 2/3.

Step-by-step explanation:

2/1 is 2, 8/9 is 1 more ninth than 7/9, and 2/3 is less third than 1.

4 0

2 years ago

Read 2 more answers

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is <span>D. 12xy^2
</span>
$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

3 0

3 years ago

It takes Sam 3 hours to rake the front lawn while his brother, Dave, can rake the lawn in 5 hours. How long will it take them to

OleMash [197]

Answer:

3 hours + 5hours = 8 hours ÷ 2 =

4 hours is your answer.

Step-by-step explanation:

If you have 2 people working and need to know how long it would take them to finish a job. Working together on the same job, you add each of their total hours to do the job alone,, 5 + 3 = 8, then divide the 8 by 2 people

equals 4 hours for 2 people on 1 job.

4 0

2 years ago