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Kruka [31]
3 years ago
8

In two or more complete sentences, describe how you would draw the graph of the solution set for the following inequality.

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

The simplified form of inequality is m > - 4. So, the solution will be the right side of x = - 4 line.  

Step-by-step explanation:

We have to draw the graph of the solution of the given inequality  - 3m + 18 < 30 ......... (1)

Step 1: Simplify the inequality as simple as possible.

-3m + 18 < 30

⇒ - 3m < 12

⇒ m > - 4 {Dividing both sides with - 3 and hence there is the change in inequality sign.}

Step 2: Now, draw the line x = - 4 in the coordinate plane. It will be a vertical line on the coordinate plane and at a distance of 4 units in the negative direction from the y-axis.

Step 3: Now, shade the portion right side of the line (As m > - 4, so the value of m will be greater than - 4)but do not include the line. (Answer)

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A regular hexagon is inscribed in a circle and another regular hexagon is circumscribed about the same circle. What is the ratio
Anna007 [38]

4/3 of the area of the larger hexagon to the area of the smaller hexagon

Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.

The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)

The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3

area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18

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Required ratio = 4/3 answer

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2 years ago
2. Flying to Kampala with a tailwind a plane averaged 158 km/h . On the return trip the plane only averaged 112 km/h while flyin
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Answer:

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

Step-by-step explanation:

Given that:

Speed of plane with the wind = 158km/h

Speed of plane against the wind = 112km/h

Let,

x be the speed of plane

y be the speed of wind

According to given statement;

x+y = 158     Eqn 1

x-y = 112       Eqn 2

Adding Eqn 1 and 2

x+y+x-y=158+112\\2x = 170\\\frac{2x}{2}=\frac{270}{2}\\x=135

Putting x = 135 in Eqn 1

135+y = 158

y = 158-135

y = 23

Hence,

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

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3 years ago
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answer is 1.566 deg

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tanθ  = H/ 240

tanθ × 240 = H

θ =( tan∧-1) 240

= <u>1.566 deg</u>

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