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steposvetlana [31]
3 years ago
13

Completa los datos que hacen folta en la tabla pitagoricacolorea de rojo los multiplos de 8 , azul los 5 ,verde los de 10 y de a

meriloo los del 3
Mathematics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

i don't understand your language broo

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QUESTION 3 Toyota provides an option of a sunroof and side airbag package for its Corolla model. This package costs $1400. Assum
Orlov [11]

Answer:

n=601

Step-by-step explanation:

Formula used:

n=z(\frac{\alpha }{2})^2\frac{p(1-p) }{E^2}

Solution:

n=z(\frac{\alpha }{2})^2\frac{p(1-p) }{E^2}

Where,

\frac{\alpha }{2}=0.025

As there is no previous estimate for p

Then, p=0.5

Here on using the table

z(\frac{\alpha }{2}) =1.959963985

Also,

E=0.04

p=0.5

Thus,

n=600.2279407

On approximating the value,

n=601

6 0
3 years ago
W=zr-2zt^3 solve for z
ladessa [460]

Answer: z=0

Step-by-step explanation:

W=zr-2zt^3

Move all terms containing z to the left, all other terms to the right.

dd '-1rz' to each side of the equation.

-1rz+z=rz+-1rz+-2t^3z

Combine like terms: rz + -1rz = 0

-1rz+z=0+(-2t^3z)

-1rz+z=-2t^3z

Add 2t^3z to each side

-1rz+2t^3z+z=-2t^3z+2t^3z

Combine the like terms 2t^3z+2t^3z=0

-1rz+2t^3z+z=0

Factor out the Greatest Common Factor (GCF), 'z'.

z(-1r+2t^3+1)=0

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

8 0
3 years ago
Which expressions are equal to the expression _2.7 _ 16.4?
Genrish500 [490]
This is just to easy the correct answer is A
8 0
3 years ago
Read 2 more answers
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
Mickey draws two distinct intersecting lines, p and q. Which conclusions must be true? Select three that apply.
timofeeve [1]

Hey there!

D is the answer.

I was thinking it might be B but no one said the lines crossed each other.

Hope this helps, Jesus loves you!

7 0
3 years ago
Read 2 more answers
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