import java.util.Scanner;
public class JavaApplication58 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a positive integer:");
String num = scan.nextLine();
for (int i = num.length()-1; i >=0; i--){
System.out.println(num.charAt(i));
}
}
}
I hope this helps!
Answer:
1.) 25 ; 15 ; 15
2.) 50 ; 15 ; 50
Explanation:
In the first function written :
The variable val was initially decaled or assigned a value of 25 and that was what was printed first.
However, after the example function was written, the val variable was finally assiagned a value of 15 within the function. However, it was also declared that the global variable takes uonthe val value. Hence, the val variable initially assigned a value, of 25 changes to 15 globally.
For the second code :
From the top:
Val was assigned a value of 50 ;
Hence,
print(val) gives an output of 50
Within the function definition which prints the value of val that is assigned a value of 25 within the function.
Since tbe global variable isnt reset.
Printing Val again outputs 50;since ito is outside the function.
Answer:
Answer explained below
Explanation:
void bubbleSort(int X[], int Y[], int n)
{
int i, j;
for (i = 0; i < n-1; i++)
// Last i elements are already in place
for (j = 0; j < n-i-1; j++)
if (X[j] > X[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
if (X[j] == X[j+1]&&Y[j]<Y[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
}
Since the above algorithm contains 2 nested loops over n.
So, it is O(n^2)
What game ? I’m not sure what ur trying to ask
