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tamaranim1 [39]
3 years ago
8

Sam has $3.30 in quarters and dimes, and the total number of coins is 18. How many quarters and how many dimes?

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

Quarters: 10

Dimes: 8

Step-by-step explanation:

Constraints

value: 0.25q + 0.10d = 3.30

count: q + d = 18

q = 18 - d

0.25(18-d) + 0.10d = 3.30

4.50-0.25d+0.10d = 3.30

4.50-0.15d = 3.30

-0.15d = -1.20

d = 8

q + d = 18

q + 8 = 18

q = 10

Check:

0.25(10) + 0.10(8) = 3.30

2.5+ 0.80 = 3.30

3.30 = 3.30

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42 = 7 ( x + 5 ) solve for x
Olegator [25]

Answer:

x = 1

Step-by-step explanation:

4 0
2 years ago
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What is the range of the function in the graph?
Verdich [7]

The range of the function in the graph given can be expressed as: D. 20 ≤ s ≤ 100.

<h3>What is the Range and Domain of a Function?</h3>

All the possible set of x-values that are plotted on the horizontal axis (x-axis) are the domain of a function. In order words, they are the inputs of the function.

On the other hand, all the corresponding set of x-values that are plotted on the vertical axis (y-axis) are the range of a function. In order words, they are the outputs of the function.

In the graph given below that shows a function, s is plotted on the vertical axis (y-axis), and its values starts from 20, up to 100. The range can be said to be all values of s that are from 20 to 100.

Therefore, the range of the function in the graph given can be expressed as: D. 20 ≤ s ≤ 100.

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3 0
2 years ago
Julio purchased some power tools totaling $2174 using a six-month deferred payment plan with an interest rate of 28.19%. He did
quester [9]
I believe you have to do a cross product formula.

2174/x = 28.19/100
8 0
3 years ago
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suppose a farmer encloses a rectangular region of a land next to a river. fencing will be used on 3 sieds, and none is needed al
nexus9112 [7]

Answer:

Dimensions :

x (the longer side, only one side with fence )   =  90  ft

y ( the shorter side two sides with fence )        =  45  ft

Total fence used   45 * 2  +  90    =  180 ft

A(max)  =  

Step-by-step explanation: If a farmer has 180 ft of fencing to encloses a rectangular area with fence in three sides and the river on one side, the farmer surely wants to have a maximum enclosed area.

Lets call "x" one the longer side  ( only one of the longer side of the rectangle will have fence, the other will be along the river and won´t need fence. "y" will be the shorter side

Then we have:

P = perimeter  =  180  =  2y  +  x        ⇒   y  =  ( 180 - x )  / 2        (1)

And   A (r)   =  x * y

A(x)   =  x  *  ( 180 - x ) /2       ⇒   A(x)   = (180/2) *x   -  x² / 2

Taking derivatives on both sides of the equation :

A´(x)   =  90   -  x    

Then if    A´(x)   =  0   ⇒        90   -  x    =  0     ⇒   x  =  90 ft

and from :       y  =  ( 180 - x )  / 2     ⇒     y  =  90/2

y  =  45  ft

And

A(max)  =  90 * 45    =  4050  ft²

4 0
3 years ago
Test again help please
netineya [11]

Answer:

4v+3 + 5v +6=180

ans is v=19

hope so its the ans

Step-by-step explanation:

mark as brainliest plzzz

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2 years ago
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