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faltersainse [42]

4 years ago

14

Will drawing an angle bisector always result in two acute angles?

1 answer:

wel4 years ago

7 0

Check the angle. If it they are less than 90°<span> , so they will result in acute angles. </span>

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What’s the answer to b,d,e and h PLEASE HELP!!! I’ll give you Brainly

Tomtit [17]

Answer:

b= 5/10

d= 24/100

e= 23/100

Step-by-step explanation:

Put them in a decimal, the you can find if it's in the 10ths place or 100ths place

5 0

3 years ago

H(x) = (x2 − 49)(x + 4)

Maru [420]

Answer:

h(x) = x³ + 4x² - 49x - 196

Step-by-step explanation:

h(x) = (x² - 49)(x + 4) <== distribute

h(x) = x²(x) - 49(x) + x²(4) - 49(4)

h(x) = x³ - 49x + 4x² - 196 <== rewrite in standard form (descending degrees)

h(x) = x³ + 4x² - 49x - 196

Hope this helps!

8 0

2 years ago

What is the compound interest on investing $600 for 3 years at 7% per annum?

Brut [27]

Answer:

After investing for 3 years at 7% interest, your $600 investment will have grown to $735.03

8 0

3 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

zheka24 [161]

$\bf{Hey\ there!}$

$\bf{Quadratic\ formula\ is:}$ $\bf{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}} \ or \ you\ could\ say\ ax^2+bx+c=0$

$\bf{\bullet\ First: subtract\ by\ 2x\ on\ your\ sides\ that\ you're\ working\ with}$

$\bf{Like:x^2+20-2x=2x-2x}$

$\bf{We\ get:x^2-2x+20=0}$

$\bf{\bullet \ a=1}\\ \bf{\bullet \ b=-2}\\ \bf{\bullet \ c=20}$

$\bf{x=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(20})}{2(1)}$

$\bf{(-2)^2-4(1)(20)=-76} \\ \\ \bf{2(1)=2}$

$\bold{-(-2)=-1(-2))=+2}$

$\bf{x=\frac{2\pm\sqrt{-76}}{2}}$

$\bf{Thus\ there\ is\ NO\ REAL\ SOLUTIONS}$

$\text{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}$

$\frak{LoveYourselfFirst:)}$

6 0

3 years ago

write a polynomial fuction f of least degree that has rational coefficients, a leading coefficient of 1, and the zeroes of 6,-3,

Amanda [17]

Answer:

$f(x)=x^3-7x^2-6x+72$

Step-by-step explanation:

$f(x)=a(x-p)(x-q)(x-r)\\\\f(x)=1(x-6)(x+3)(x-4)\\\\f(x)=(x^2-3x-18)(x-4)\\\\f(x)=x^3-4x^2-3x^2+12x-18x+72\\\\f(x)=x^3-7x^2-6x+72$

This is because $x=6$ is the solution to $x-6=0$ , $x=-3$ is the solution to $x+3=0$ , and $x=4$ is the solution to $x-4=0$ .

3 0

2 years ago