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musickatia [10]
4 years ago
7

The point (5, -1) is a solution of the equation: y = 2x − 11 question 28 options: true false

Mathematics
1 answer:
kkurt [141]4 years ago
8 0
True
This is because on replacing for x=5;
y=2x-11
y=2(5)-11
y=10-11
y=-1

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Refer to the accompanying technology display. The probabilities in the display were obtained using the values of n equals n=5 an
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Answer:

<u><em></em></u>

  • <u><em>Yes, it is reasonable to expect that more than one subject will experience​ headaches</em></u>

Explanation:

Notice that where it says "assume that 55 subjects are randomly selected ..." there is a typo. The correct statement is "assume that 5 subjects are randomly selected ..."

You are given the table with the probability distribution, assuming, correctly, the binomial distribution with n = 5 and p = 0.732.

  • p = 0.732 is the probability of success (an individual experiences headaches).
  • n = 5 is the number of trials (number of subjects in the sample).

The meaning of the table of the distribution probability is:

The probability that 0 subjects experience headaches is 0.0014; the probability that 1 subject experience headaches is 0.0189, and so on.

To answer whether it <em>is reasonable to expect that more than one subject will experience​ headaches</em>, you must find the probability that:

  • X = 2 or X = 3 or X = 4 or X = 5

That is:

  • P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5).

That is also the complement of P(X = 0) or P(X = 1)

  • 1 - P(X = 0) - P(X = 1)

From the table:

  • P(X = 0) = 0.0014
  • P(X = 1) = 0.0189

Hence:

  • 1 - P(X = 0) - P(X = 1) = 1 - 0.0014 - 0.0189 = 0.9797

That is very close to 1; thus, it is highly likely that more than 1 subject will experience headaches.

In conclusion, <em>yes, it is reasonable to expect that more than one subject will experience​ headaches</em>

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