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Alik [6]
3 years ago
11

Use a Taylor series to approximate the following definite integrals. Retain as many terms as needed to ensure the error is less

than 10−4. ∫0.201+x4−−−−−√dx
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0

Answer:

I= 0.40102036

Step-by-step explanation:

∧ = raise to power

Given the equation

F(x) = √x² + 1.0

Now recalling the Taylor Series in respect to the approximation  for degree n at x = a....

Therefore, it is given by :

f(x) = f(a) + f° (a) ((x - a)) + ( 1/2) f°° (a)((x -a)² + .....(1/n!) f∧n (a) ((x - a) ∧ n

Referring back to the Taylor Series

f(x) = - x ∧8/8 + x ∧ 4/2 + 1

If we integrate the Taylor series, we get,

f°(x) = - x ³*³/72 + x∧5/10 + x

At this point, we apply limit (lim) to the integrals

I = ∫ lim(0.4) (0) f(x) dx

I = ∫ (- x ∧8/8 + x ∧ 4/2 +1)dx

I = [ ( -x³*³/72 + x∧5/10 +x)]lim(0.4) lim(0)

The final answer then is:

I= 0.40102036

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The area of a segment of a circle is the area of the corresponding sector of the circle _____ the area of the corresponding tria
madreJ [45]

Answer:

The area of a segment of a circle is the area of the corresponding sector of the circle  <u>minus</u> the area of the corresponding triangle.

Step-by-step explanation:

We know area of segment of a circle is the area of the corresponding sector of the circle minus the area of the corresponding triangle.

5 0
3 years ago
Pls anwers the question pls it has pictures as well pls pls pls pls pls pls pls
azamat

Answer:

a = $80.3

b = $80

c = 4

d = 16

e = 4

f = 88

g = $132

h = 33%

i = 6

j = 30

k = 21

l = $90

m = $36

o = 21/50

p = 105

q = 7

r = 8 cm

s = 2.4

t = 4

u = 400cm

v = $280

Step-by-step Explanation:

==>Increasing $72 by 10% to get a

a = 110% of $72 = 110% × $73

a = 1.1 × 73

a = $80.3

==>a ($80.3) rounded to the nearest 10 to find b = $80

b = $80

==>Writing b (80) as the product of its primes I.e.

b = 2^{c} * 5

Thus, 80 = 2⁴ * 5

c = 4

==>Calculating c² = d

d = 4² = 16

d = 16

==> ²/8 of d = e

e = ²/8 × 16

e = 2 × 2

e = 4

==> e% of 2200 = f

f = 4% × 2200

f = 0.04 × 2200

f = 88

==>Converting £f to $ = g

If £1 = $1.5,

£88 = $g

1 × g = 1.5 × 88

g = $132

==> Converting \frac{g}{400} into % = h%

h = 132÷400 ×100

h = 0.33 × 100

h = 33%

==> √(h + 3) = i

i = √(33 + 3)

i = √36

i = 6

==> i × (3 + 2) = j

j = 6 × (3 + 2)

j = 6 × 5

j = 30

==> j% of 70 = k

k = j% × 70

k = 30% × 70

k = 0.3 × 70

k = 21

==> If k bottles = $63, 30 bottles = $l

21 bottles = $63

30 bottles = $l

21 × l = 63 × 30

21l = 1,890

l = 1,890/21

l = $90

==>If Tim and Mike (m) shares $90 in the ratio 3:2, Mike (m) would receive thus:

⅖ × $90 = m

m = 0.4 × 90

m = $36

==> √m + m = n

n = √36 + 36

n = 6 + 36

n = 42

==>Converting n% to fraction = o

Thus, o = 42/100

o = 21/50

==> o of 250 = p

p = 21/50 × 250

p = (21 × 250)/50

p = 21 × 5

p = 105

==> expressing p as a product of its primes i.e. p = 3 × 5 × q

105 = 3 × 5 × 7

Therefore, q = 7

==> Given a rectangle with dimensions of q cm and r cm, with an area of 56cm². Let's find r.

Area of rectangle = length × width = q × r

Area = 56 cm²

q = 7 cm

r = ?

56 = 7 × r

56/7 = r

8 = r

r = 8 cm

==> r × 0.3 = s

s = 8 × 0.3

s = 2.4

==> s ÷ 0.6 = t

t = 2.4 ÷ 0.6

t = 4

==> If t is in meters, converting t to cm will give us u

Since 1m = 100cm

4m = u cm

1 × u = 100 × 4

u = 400cm

==> Vikki (v) and John shares $u in the ratio 7:3. Thus, Vikki (v) would receive the following:

v = ⁷/10 × $400

v = 0.7 × 400

v = $280

8 0
3 years ago
Find the surface area of the figure
IgorLugansk [536]

Answer:

Area of a Square it base x height so 4x4=16+16 = 32 in^2

Step-by-step explanation:

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3 years ago
I will mark you brainliest just give me the answer please. (I suck at math a lot.) 2s + 7 &lt; 13: 1, 2, 3
AleksandrR [38]

Answer:

3

Step-by-step explanation:

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4 0
3 years ago
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
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