3/4 the lower denominator is always the greatest.. Remember That!;)
I think is f(1) not g(1)
f(x) = -3x + 8
subtitute the value of x = 1 to the equation:
f(1) = -3(1) + 8 = -3 + 8 = 5
Step-by-step explanation:
For a quadratic equation y = ax² + bx + c, the vertex (the maximum or minimum point) is at x = -b/(2a).
1) y = -0.5t² + 2t + 38
The maximum is at:
t = -2 / (2 × -0.5)
t = 2
The maximum height is:
y = -0.5(2)² + 2(2) + 38
y = 40
The coordinates of the vertex are (2, 40). That means the missile reaches a maximum height of 40 km after 2 minutes.
2) y = -4.9t² + 12t + 1.6
The maximum is at:
t = -12 / (2 × -4.9)
t = 1.22
The maximum height is:
y = -4.9(1.22)² + 12(1.22) + 1.6
y = 8.95
The coordinates of the vertex are (1.22, 8.95). That means the missile reaches a maximum height of 8.95 m after 1.22 seconds.
3) y = -0.04x² + 0.88x
The maximum is at:
x = -0.88 / (2 × -0.04)
x = 11
The maximum height is:
y = -0.04(11)² + 0.88(11)
y = 4.84
The maximum height of the tunnel is 4.84 meters.
The maximum width is when y = 0.
0 = -0.04x² + 0.88x
0 = -0.04x (x − 22)
x = 22
The maximum width is 22 feet.
You would be able to get 6 liters of milk.
(6.72 x 4)/4.48 = 6
Swing an arc the length of the radius from the point on the circle
Step-by-step explanation:
When constructing a square inscribed in a circle, you first draw the circle.This is followed by drawing the diameter of the circle.Using a pair of compass, construct a segment bisector of the diameter, and draw the perpendicular bisector to cut the circle at two points .Join the points cut by the diameter and the bisector on the circle to form the inscribed square.
Swinging an arc the length of the radius from the point on the circle will not mark the correct length of the square.The correct length of the square is marked by the points cut by the diameter and the bisector on the circle.
Learn More
Construction of inscribed square :brainly.com/question/13152465
Keywords : statement, inscribed square
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