Question

Write a function named wordLineCount with the following input and output: Input: a string parameter, inFile, that is the name of a file Output: return a dictionary in which each unique word in inFile is a key and the corresponding value is the number of lines on which that word occurs The file inFile contains only lower case letters and white space. For example, if the file ben.txt contains these lines tell me and i forget teach me and i remember involve me and i learn then the following would be correct output:
>>> print(wordLineCount('ben.txt')){'remember': 1, 'and': 3, 'tell': 1, 'me': 3, 'forget': 1, 'learn': 1,'involve': 1, 'i': 3, 'teach': 1}

Answer 1

Answer:

def wordLineCount(file):

   dic = {}

   with open(file,'r') as file:

       

       text = file.read()

       text = text.strip().split()

       for word in text:

           if word in dic:

               dic[word] += 1

           else:

               dic[word] = 1

   return dic

print(wordLineCount('ben.txt'))

Explanation:

The programming language used is python.

The program starts by defining the function, an empty dictionary is created to hold the words and the number of times that they occur. the with key word is used to open the file, this allows the file to close automatically as soon as the operation on it is finished.

The data in the file is read to a variable text, it is striped from all punctuation and converted to a list of words.

A FOR loop and an if statement is used to iterate through every word in the list and checking if they are already in the dictionary. if the word is already contained in the dictionary, the number of occurrences increases by one. otherwise, it is added to the dictionary.

check the attachment to see code in action.