The value (9/10)*81 is greater than (5/6)*81
<h3>How to determine the greater value?</h3>
The values are given as:
(5/6)*81 and (9/10)*81
Remove the common factor in both values
So, we have:
5/6 and 9/10
Convert to decimals
0.83 and 0.9
0.9 is greater than 0.83
Hence, (9/10)*81 is greater than (5/6)*81
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Forty and ninety nine hundreths
Hello!
You solve this algebraically
6(3 - 2x) = 54
distribute the 6
18 - 12x = 54
Subtract 18 from both sides
-12x = 36
Divide both sides by -12
x = -3
The answer is -3
Hope this helps!
Let Joy be x years old
<span>Joy's brother's age is 3 years older than twice joy's age.
</span>Joy's Brother = 2x + 3
<span>The sum of Joy's age and her brother's age is 24.
x + 2x + 3 = 24
3x + 3 = 24
3x = 24 - 3
3x = 21
x = 21 </span>÷ 3
x = 7
Joy:
x = 7
Brother:
2x + 3 = 2(7) + 3 = 17
Difference in their age = 17 - 7 = 10 years
They are 10 years apart.