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KonstantinChe [14]
3 years ago
14

11×+2-4x-x-216-13x+24-39​

Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:

-12x

Step-by-step explanation:

16-13x=3x

24-39=-15

3+-15=-12x

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Akira Chang's uncle dies without a will, leaving an estate of $945,000. His heirs consist of a wife and two adult children. His
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Let w represent the amount the wife receives.
.. w +2*(2/3*w) = 945,000
.. 7/3w = 945,000
.. w = (3/7)*945,000 = 405,000

The wife will receive $405,000.
5 0
3 years ago
Keith exercises x hours a week. Troy exercises three hours less than Keith and Joe exercises two times more than Troy. Which exp
muminat
If you would like to know which expression represents the amount of time Joe exercises, you can calculate this using the following steps:

Keith ... x hours a week
Troy ... three hours less than Keith: x - 3
Joe ... two times more than Troy: 2 * (x - 3)

The correct result would be D) 2 * (x - 3).
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Here's a graph of a linear function. Write the equation that describes that function.
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In the data set below, what is the interquartile range?<br> 7<br> 1<br> 5<br> 5<br> 9<br> Submit
Marizza181 [45]

Answer:

5

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1  5  5  7  9 ← data in ascending order

       ↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1  5

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The upper quartile is the middle value of the data to the right of the median.

7  9

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<h3>What is the Tangent Ratio?</h3>

In a right triangle, tan ∅ = opposite length / adjacent length is the tangent ratio.

Given the following:

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  • Opposite length = 125 ft
  • Adjacent length = 172 ft

Apply the tangent ratio:

tan ∅ = 125/172

tan ∅ = 125/172

∅ = tan^(-1)(125/172)

∅ ≈ 36°

Learn more about the tangent ratio on:

brainly.com/question/4326804

#SPJ1

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